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3 years ago

I don’t know this please help

Mathematics

2 answers:

dolphi86 [110]3 years ago

8 0

The slope is:

--------

The y-intercept is

-3

Please let me know if im wrong, but if im right I want brainliest, PLEASE!!!

Vadim26 [7]3 years ago

7 0

Answer:

slope is up 8 over 5

y-intercept is 0,-3

Step-by-step explanation:

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3 years ago

The graph shows the functions f(x), p(x), and g(x):

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2 years ago

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago

examine the diagram to the right then use the information provided in the diagram to find the measures of angles x , y, z. For e

sergiy2304 [10]

Answer:

Step-by-step explanation:

The letters are virtually impossible to read. I'll do my best, but recognize it is why you are not getting answers. I take y to be next to the 100 degree angle and part of the triangle.

I take x to be to the left of y. It is equal to the 28o angle because of the tranversal properties.

Finally z is the exterior angle of the triangle and as such has properties of z = y + 28 where y and 28 are remote interior angles to the triangle.

so x = 28 because of the transversal cutting the two parallel lines. They are equal by remote exterior angles of parallel lines.

y = 180 - 100 - 28 = 52

Finally z = 52 + 28 = 80 degrees because x and y add to 80 degrees.

If the assumptions are incorrect, could I trouble you to repost the diagram or correct the errors I have made.

4 0

2 years ago