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3 years ago

I don’t know this please help

Mathematics

2 answers:

dolphi86 [110]3 years ago

8 0

The slope is:

--------

The y-intercept is

-3

Please let me know if im wrong, but if im right I want brainliest, PLEASE!!!

Vadim26 [7]3 years ago

7 0

Answer:

slope is up 8 over 5

y-intercept is 0,-3

Step-by-step explanation:

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2y+8x=1 in slope intercept form

anzhelika [568]

The slope-intercept form is y = mx + b.
Following that kind of form becomes
2y = -8x + 1
y =(-8x + 1)/2
y = -4x + 1/2

Hope this helps <span>✌️</span>☺️✌️

6 0

3 years ago

63x^12-35x^6 help pls

zmey [24]

Answer:

7x^6×(9×^6-5)

Step-by-step explanation:

63x^12-35x^6

7x^6×(9×^6-5)

7 0

2 years ago

For the x-values 1, 2, 3, and so on, the y-values of a function form

OlgaM077 [116]

Answer:

A. Decreasing linear

Step-by-step explanation:

6 0

2 years ago

Find the limit, if it exists, or type dne if it does not exist.

Phantasy [73]

$\displaystyle\lim_{(x,y)\to(0,0)}\frac{\left(x+23y)^2}{x^2+529y^2}$

Suppose we choose a path along the $x$ -axis, so that $y=0$ :

$\displaystyle\lim_{x\to0}\frac{x^2}{x^2}=\lim_{x\to0}1=1$

On the other hand, let's consider an arbitrary line through the origin, $y=kx$ :

$\displaystyle\lim_{x\to0}\frac{(x+23kx)^2}{x^2+529(kx)^2}=\lim_{x\to0}\frac{(23k+1)^2x^2}{(529k^2+1)x^2}=\lim_{x\to0}\frac{(23k+1)^2}{529k^2+1}=\dfrac{(23k+1)^2}{529k^2+1}$

The value of the limit then depends on $k$ , which means the limit is not the same across all possible paths toward the origin, and so the limit does not exist.

8 0

3 years ago

There are 15 students on a yearbook committee. 40% of the students are females. How many students on the committee are males?

Andrei [34K]

Answer:

9 students on the committee are males

Step-by-step explanation:

As per the statement:

There are 15 students on a yearbook committee.

⇒Total students on a yearbook committee = 15

⇒ $\text{Male students} +\text{Female students} = 15$ ....[1]