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Gelneren [198K]
3 years ago
14

Please HELPppppppppppppppp

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
6 0

Answer:

Point of intersections are (0, -7) and (5, -2).

Step-by-step explanation:

From the graph attached,

A straight line is intersecting the circle at the two points (0, 7) and (5, -2).

Now solve algebraically,

Equation of the line → y = x - 7 -------(1)

Equation of the circle → (x - 5)² + (y + 7)² = 25 -------(2)

By substituting the value of y from equation (1) to equation (2)

(x - 5)² + (x - 7 + 7)² = 25

(x - 5)² + x² = 25

x² - 10x + 25 + x² = 25

2x² - 10x = 0

x² - 5x = 0

x(x - 5) = 0

x = 0, 5

From equation (1),

y = 0 - 7 = -7

y = 5 - 7 = -2

Therefore, point of intersections are (0, -7) and (5, -2).

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Any help please? For extra credit
Law Incorporation [45]

Answer:

see explanation

Step-by-step explanation:

(a)

A recursive formula allows any term in the sequence to be found by adding the common difference d to the previous term.

Here d = - 4 , then recursive formula is

a_{n} = a_{n-1} - 4 with a₁ = 2

(b)

The explicit formula for an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 2 and d = - 4, thus

a_{n} = 2 - 4(n - 1) = 2 - 4n + 4 = 6 - 4n ← explicit formula

(c)

Using the recursive formula

a₁ = 2

a₂ = 2 - 4 = - 2

a₃ = - 2 - 4 = - 6

Using the explicit formula

a₅ = 6 - 4(5) = 6 - 20 = - 14

a₁₀ = 6 - 4(10) = 6 - 40 = - 34

a₁₀₀ = 6 - 4(100) = 6 - 400 = - 394

4 0
2 years ago
Use​ Newton's method to find an approximate solution of ln(x)=10-x. Start with x_0 =9 and find x_2 .
vova2212 [387]

Answer:

x₂ = 7.9156

Step-by-step explanation:

Given the function  ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ -  f(xₙ)/f'(xₙ)

If f(x) = ln(x)+x-10

f'(x) = 1/x + 1

f(9) = ln9+9-10

f(9) = ln9- 1

f(9) = 2.1972 - 1

f(9) = 1.1972

f'(9) = 1/9 + 1

f'(9) = 10/9

f'(9) = 1.1111

x₁ = x₀ -  f(x₀)/f'(x₀)

x₁ = 9 -  1.1972/1.1111

x₁  = 9 - 1.0775

x₁  = 7.9225

x₂ = x₁ -  f(x₁)/f'(x₁)

x₂ = 7.9225 -  f(7.9225)/f'(7.9225)

f(7.9225) = ln7.9225 + 7.9225 -10

f(7.9225) = 2.0697 + 7.9225 -10

f(7.9225) = 0.0078

f'(7.9225) = 1/7.9225 + 1

f'(7.9225) = 0.1262+1

f'(7.9225) = 1.1262

x₂ = 7.9225 - 0.0078/1.1262

x₂ = 7.9225 - 0.006926

x₂ = 7.9156

<em>Hence the approximate value of x₂ is 7.9156</em>

7 0
3 years ago
GIVING BRAILEST<br> Describe a situation that the equation could represent g+3<br> _____ =15<br> 6
krek1111 [17]

Answer:

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Step-by-step explanation:

i hope this helped...

6 0
2 years ago
Approximating square root of 17 to the nearest hundredth.
Juliette [100K]

Answer:

4.12

Step-by-step explanation:

\sqrt{17} = 4.1231 ≈ 4.12

6 0
3 years ago
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