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prohojiy [21]
3 years ago
15

Which property of equality would you use to solve the equation 14x=56

Mathematics
1 answer:
Oliga [24]3 years ago
4 0
Okay so divide 56 by 14 and so x = 4
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The main cables of a suspension bridge are ideally parabolic. the cables over a bridge that is 400 feet logn are attached to tow
Novay_Z [31]
Consider the diagram of the problem.

Let the vertex be on the y axis, exactly, at the point (0, 40)

Another point of this parabola is (200, 100), as can be checked from the figure.

The vertex form of the equation of a parabola is :

y=a(x-h)^{2}+k, where (h, k) is the vertex of the parabola, 

replacing (h, k) with (0, 40), we have:

y=ax^{2}+40

to find a, we substitute (x, y) with (200, 100):

100=a200^{2}+40

40,000a=60

a=60/40,000=3/(2,000)

So, the equation of the parabola is y= \frac{3}{2000} x^{2}+40

4 0
3 years ago
2. What is the vertex of the following parabola? *
sweet [91]

Answer:

42

Step-by-step explanation:

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7 0
2 years ago
How can I learn to do standard notation and scientific notation?
jonny [76]
Just watch videos on youtube.
5 0
3 years ago
The perimeter of this isosceles triangle is 22 cm. If one side is 6 cm, what are the possible lengths of the other two sides? Pa
3241004551 [841]
We know that

<span>the isosceles triangle has two equal sides
</span>
<span>let's analyze two cases
</span>
first case
perimeter=22 cm
<span>let's suppose that the known side of 6 cm is one of the two equal sides
</span>perimeter=6+6+x
22=6+6+x-----> x=22-12----> x=10 cm

answer first case
<span>the possible lengths of the other two sides are
</span>6 cm 
10 cm

second case
let's suppose that the known side of 6 cm is the side that is not equal
perimeter=22 cm
perimeter=6+x+x
22=6+x+x----> 2x=22-6----> 2x=16-----> x=8 cm


answer second case
the possible lengths of the other two sides are
8 cm 
8 cm

4 0
3 years ago
What is 6,4 rounded to the nearest whole number
Aleks04 [339]
6.4 rounded to the nearest whole number will be 6.

if the decimal was 5 or larger, it would’ve been 7.
6 0
3 years ago
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