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8090 [49]
3 years ago
10

Is MS DOS a network operating system?​

Computers and Technology
1 answer:
chubhunter [2.5K]3 years ago
7 0

Answer:

Operating systems now use networks to make peer-to-peer connections and also connections to servers for access to file systems and print servers. The three most widely used operating systems are MS-DOS, Microsoft Windows and UNIX.

Explanation:

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Look at the pic. I know what girls be going through like us girls aren't toys. Please stop, please.
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No need to be overly-sensitive, brainly deleted that question

If no one joins then its not a problem

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Write an application that reads the lengths of the sides of a triangle from the user. compute the area of the triangle using her
zlopas [31]

Here you go,


import java.util.Scanner;

import java.util.Random;

public class OrderCalculator{


public static void main(String[] args){  


float x, y, z, semi, area;

Scanner in = new Scanner(System.in);

System.out.print("Enter the 3 sides: ");

x = in.nextFloat();

y = in.nextFloat();

z = in.nextFloat();

semi = (float) ((x + y + z) / 2.0);

area = (float) Math.sqrt(semi * (semi - x) * (semi - y) * (semi - z));

System.out.printf("The area is: %.3f\n", area);


}

}

3 0
3 years ago
3. The wildlife department has been feeding a special food to rainbow trout finger lings in a pond. A sample of the weight of 40
andrey2020 [161]

Answer:

1)  402.7 grams. This estimate is called the sample mean.

2)  (399.11, 406.29)

3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.

I am 99% sure that the value lies between 399.11 grams and 406.29 grams.

Explanation:

sample size (n) = 40, the mean weight (x)= 402.7 grams and the standard deviation (σ)=8.8 grams

1) The point estimated mean weight of the population is 402.7 grams. This estimate is called the sample mean.

2) c = 99% = 0.99

α = 1 - 0.99 = 0.01

\frac{\alpha }{2} =\frac{0.01}{2} =0.005.

The z score of 0.005 corresponds with the z score of 0.495 (0.5 - 0.005).

z_\frac{\alpha }{2} =2.58.

The margin of error (e) = z_\frac{\alpha }{2}*\frac{\sigma}{\sqrt{n} }  =2.58*\frac{8.8}{\sqrt{40} } =3.59

The confidence interval = x ± e = 402.7 ± 3.59 = (399.11, 406.29)

3) The 99 percent confidence limits is between 399.11 grams and 406.29 grams.

I am 99% sure that the value lies between 399.11 grams and 406.29 grams.

8 0
3 years ago
Subjects with a lot of ___ make focusing easier.
Elden [556K]

Answer:

things is the correct answer

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Explain different types of port?​
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Answer:

.serial port

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4 0
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