Answer:
A. Detecting network attacks and scans
Explanation:
Honeynet
It is a network , which is set up with the intentional vulnerabilities , in order to invite the attack , in order to determine and study the activities of the attacker .
The Honeynet is composed of one or more honey pots , which are just the computer systems , which act as a bait to trap the people who , tries to hack or penetrate into other's computer system .
Hence ,
The correct option is Detecting network attacks and scans .
Well Here I got 4
1. Email Functions
2. Distributing Payments
3. Record Keeping
4. Direct Mail Promotions
<em>Have A great night!</em>
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Answer:
The requirement of the virtualization in the operating system:
• The virtualization of the resources from single systems input can be partitioned into a small virtual environment in multiple system data processes.
• Virtualization can collect the physical system's hardware and software data, they can transfer the virtualization process and also verify that the working system is running properly.
• Virtualization has to determine the specific components such as workload, file location, network traffic and console administration process. The requirement for moving into the virtual environment must be selected based on windows for the operating system(32-bit), windows host operating system(4-bit) and Linux operating system.
Answer:
#include <stdio.h>
int hexToDec(const int hexNum[]){
int result = 0, prod = 1;
for(int i = 3;i>=0;i-=1){
result += (prod*hexNum[i]);
prod = prod * 16;
}
return result;
}
int main()
{
int hexNum[4], i;
char s[5], ch;
printf("Enter hexa decimal value: ");
scanf("%s",s);
for(i = 0;i<4;i++){
ch = s[i];
if(ch>='0' && ch<='9'){
hexNum[i] = ch-'0';
}
else if((ch>='a' && ch<='f') || (ch>='A' && ch<='F')){
if(ch=='A' || ch=='a'){
hexNum[i] = 10;
}
else if(ch=='B' || ch=='b'){
hexNum[i] = 11;
}
else if(ch=='C' || ch=='c'){
hexNum[i] = 12;
}
else if(ch=='D' || ch=='d'){
hexNum[i] = 13;
}
else if(ch=='E' || ch=='e'){
hexNum[i] = 14;
}
else{
hexNum[i] = 15;
}
}
}
printf("%d",hexToDec(hexNum));
return 0;
}
Explanation:
