Answer:
The probability that there is at least one pair but not a three of a kind is 0.6944.
Step-by-step explanation:
We have the case when we have five dices and we roll them and we need that there is at least one pair but not a three of a king which is Two dice showing the same value, but no three dice showing the value.
Total no of outcomes = 
We will consider the other cases and then subtract them from the total outcomes.
No of outcomes of 5 of a kind = 6
No of outcomes 4 of a kind and 1 different = (6*5)*5 = 150
No of outcomes with 3 of a kind and 1 different pairs = (6*1*1*5*1)*5C2= 300
No of outcomes with 3 of a kind and two different = 6*5*4*10= 120*10=1200
No of outcomes when all are different = 6! = 720
These all the cases when subtracted from the total will represent the total cases in which there are two dice showing the same value.
Total cases = 6+150+300+1200+720
= 2376
Required no of outcomes = 7776-2376 = 5400
Probability =
= 0.6944
Therefore the probability for the case of at least one pair but not a three of a kind is 0.6944.
Answer:
cm
Step-by-step explanation:
Given dimensions:
cm by
cm by
cm
The total length:
it is the sum of all the sides;
LCM of the denominators = 6 ;
= 
=
=
cm
Let the retail cost be x and the wholesale cost be y. From the first statement, we can formulate the equation written below:
x = y + 0.45y
x = 1.45y
Therefore, the retail cost is 1.45 times greater than the wholesale cost.
So for a mother ages 28 , there is a chance of 1 in 1000 , but at the age of 38 there is a chance of 1 in 200 . to work out how many times more likely it is for the 38 year old to give birth to a child with down syndrome is to divide 1000 by 200 and this gives us 5 . so the 38 year old is 5 times more likely to give birth to a child with down syndrome than a 28 year old :)