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MAXImum [283]
3 years ago
13

Step 1: Calculate the measures of center for Mrs. Hampton's data in the dot plot (round your answer to the nearest tenths place)

. Show your work and briefly explain each step. (Measures of Center are the Mean and Median of a data set)

Mathematics
1 answer:
Deffense [45]3 years ago
8 0

*dot plot is shown in the attachment below

Answer:

Mean = 6.3

Median = 6

Step-by-step explanation:

Measures of centre, mean and median, can be calculated as follows:

First, bear in mind that each dot represents a value in the data set.

==>Mean:

Mean is the sum of all values in the data set divided by the number of data set we have.

The sum can be calculated as follows:

0 (1) = 0

4 (3) = 12

5(8) = 40

6(3) = 18

7(1) = 7

8(5) = 40

9(2) = 18

10 (3) = 30

Sum = 0+12+40+18+7+40+18+30 = 165

No of data set = 26

Mean = 165/26 = 6.346 ≈ 6.3 (nearest tenth place)

==>Median: this is the middle value in the data set. Since the number of data set is even number (26) , the middle value lies between the 13th and 14th data points. The average of the 13th and 14th data points will give us the median value.

Thus, the 13th and 14th values are both 6.

Therefore, median = (6+6) ÷ 2 = 6

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Each of five, standard, six-sided dice is rolled once. What is the probability that there is at least one pair but not a three-o
zavuch27 [327]

Answer:

The probability that there is at least one pair but not a three of a kind is 0.6944.

Step-by-step explanation:

We have the case when we have five dices and we roll them and we need  that there is at least one pair but not a three of a king which is Two dice showing the same value, but no three dice showing the value.

Total no of outcomes = 6^5 = 7776

We will consider the other cases and then subtract them from the total outcomes.

No of outcomes of 5 of a kind = 6

No of outcomes 4 of a kind and 1 different = (6*5)*5 = 150

No of outcomes with 3 of a kind and 1 different pairs = (6*1*1*5*1)*5C2= 300

No of outcomes with 3 of a kind and two different = 6*5*4*10= 120*10=1200

No of outcomes when all are different = 6! = 720

These all the cases when subtracted from the total will represent the total cases in which there are two dice showing the same value.

Total cases = 6+150+300+1200+720

                   = 2376

Required no of outcomes = 7776-2376 = 5400

Probability = \frac{5400}{7776} = 0.6944

Therefore the probability for the case of at least one pair but not a three of a kind is 0.6944.

4 0
3 years ago
the sides of a triangle are 3 whole 1 by 6 cm 4 whole 2 by 3 cm and 5 whole 2 by 3 cm. Find the total length of the three sides
Lyrx [107]

Answer:

16\frac{2}{3}cm

Step-by-step explanation:

Given dimensions:

           3\frac{1}{6} cm by 4\frac{2}{3}cm  by 5\frac{2}{3} cm

The total length:

 it is the sum of all the sides;

         \frac{19}{6}  + \frac{14}{3}   + \frac{17}{3}  

LCM of the denominators = 6 ;

   \frac{38 + 28 + 34}{6}  = \frac{100}{6}

                 = \frac{50}{3}

                 = 16\frac{2}{3}cm

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3 years ago
Find the volume of a cone with a base radius of 6ft and a height of 6ft. Write the exact volume in terms of PI, and be sure to i
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Answer:

36?

Step-by-step explanation:

7 0
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vichka [17]
Let the retail cost be x and the wholesale cost be y. From the first statement, we can formulate the equation written below:

x = y + 0.45y
x = 1.45y
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