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3 years ago

HELPPP MEEE PLEASSSE ASAP IT WOULD MEAN ALOT

Mathematics

2 answers:

KonstantinChe [14]3 years ago

5 0

Answer:

88°

Step-by-step explanation:

Here you have 2 parallel lines (with red arrows) intersecting another line. As such angle 2 would necessary have to be 92°.

Hence angle 1 would be,

180° - 92° = 88°

Delicious77 [7]3 years ago

4 0

Answer:92

Step-by-step explanation:

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Which of the following conditions must be met to conduct a two-proportion significance

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2 years ago

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2 years ago

As you were organizing your closet you counted 20 shirts and 12 pairs of pants what was the pants to shirt ratio?

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Step-by-step explanation:

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2 years ago

Find the exact value of cos(sin^-1(-5/13))

son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

$\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}$

$\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}$

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0

2 years ago