Given:
13/8
First you have to see how many times 8 can go into the number 13. If you look, 8 can only go into 13 one time, leaving 5 left over.
13-8 = 5
1 with 5 left over
(Rather than writing 8/8, you must simplify to 1 to make it less redundant)
Since there is 5 left over from 8, you would then place it into the numerator place to get:
1 5/8
I hope this helps!
Answer:
in total 5 hours
Using proportions part/whole, percent/100 you put the 40 in the percent spot and the 2 in the part spot cross multiply and divide so 2 x 100 divided by 40 and you get 5
Answer:
H=-12
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
h/6-1=-3
1/6h+-1=-3
1/6h-1=-3
Step 2: Add 1 to both sides.
1/6h+1=-3+1
1/6h=-2
Step 3: Multiply both sides by 6.
6*(1/6h)=6*(-2)
H=-12
Hope this helps
1)
here, we do the left-hand-side
![\bf [sin(x)+cos(x)]^2+[sin(x)-cos(x)]^2=2 \\\\\\\ [sin^2(x)+2sin(x)cos(x)+cos^2(x)]\\\\+~ [sin^2(x)-2sin(x)cos(x)+cos^2(x)] \\\\\\ 2sin^2(x)+2cos^2(x)\implies 2[sin^2(x)+cos^2(x)]\implies 2[1]\implies 2](https://tex.z-dn.net/?f=%5Cbf%20%5Bsin%28x%29%2Bcos%28x%29%5D%5E2%2B%5Bsin%28x%29-cos%28x%29%5D%5E2%3D2%0A%5C%5C%5C%5C%5C%5C%5C%0A%5Bsin%5E2%28x%29%2B2sin%28x%29cos%28x%29%2Bcos%5E2%28x%29%5D%5C%5C%5C%5C%2B~%20%5Bsin%5E2%28x%29-2sin%28x%29cos%28x%29%2Bcos%5E2%28x%29%5D%0A%5C%5C%5C%5C%5C%5C%0A2sin%5E2%28x%29%2B2cos%5E2%28x%29%5Cimplies%202%5Bsin%5E2%28x%29%2Bcos%5E2%28x%29%5D%5Cimplies%202%5B1%5D%5Cimplies%202)
2)
here we also do the left-hand-side
![\bf \cfrac{2-cos^2(x)}{sin(x)}=csc(x)+sin(x) \\\\\\ \cfrac{2-[1-sin^2(x)]}{sin(x)}\implies \cfrac{2-1+sin^2(x)}{sin(x)}\implies \cfrac{1+sin^2(x)}{sin(x)} \\\\\\ \cfrac{1}{sin(x)}+\cfrac{sin^2(x)}{sin(x)}\implies csc(x)+sin(x)](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B2-cos%5E2%28x%29%7D%7Bsin%28x%29%7D%3Dcsc%28x%29%2Bsin%28x%29%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B2-%5B1-sin%5E2%28x%29%5D%7D%7Bsin%28x%29%7D%5Cimplies%20%5Ccfrac%7B2-1%2Bsin%5E2%28x%29%7D%7Bsin%28x%29%7D%5Cimplies%20%5Ccfrac%7B1%2Bsin%5E2%28x%29%7D%7Bsin%28x%29%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ccfrac%7B1%7D%7Bsin%28x%29%7D%2B%5Ccfrac%7Bsin%5E2%28x%29%7D%7Bsin%28x%29%7D%5Cimplies%20csc%28x%29%2Bsin%28x%29)
3)
here, we do the right-hand-side
How do linear, quadratic, and exponential functions compare?
Answer:
How can all the solutions to an equation in two variables be represented?
<u><em>The solution to a system of linear equations in two variables is any ordered pair x,y which satisfies each equation independently. U can Graph, solutions are points at which the lines intersect.</em></u>
<u><em /></u>
<u><em>How can all the solutions to an equation in two variables be represented?</em></u>
<u><em>you can solve it by Iterative method and Newton Raphson's method.</em></u>
<u><em /></u>
<u><em>How are solutions to a system of nonlinear equations found?
</em></u>
Solve the linear equation for one variable.
Substitute the value of the variable into the nonlinear equation.
Solve the nonlinear equation for the variable.
Substitute the solution(s) into either equation to solve for the other variable.
<u><em>
</em></u>
<u><em>How can solutions to a system of nonlinear equations be approximated? U can find the solutions to a system of nonlinear equations by finding the points of intersection. The points of intersection give us an x value and a y value. Using the example system of nonlinear equations, let's look at how u can find approximate solutions.</em></u>
