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Andru [333]
3 years ago
14

Sophia is buying party favors. She has a budget of $2.75 person for 6 people. How much can Sophia spend on party favors? (I need

an equation for finding the answer too)
Mathematics
1 answer:
yKpoI14uk [10]3 years ago
4 0
Let x represent the amount of money Sophia can spend on party favors. 

x = amount of money Sophia can spend 
$2.75 = amount spent per person
6 = amount of people

Equation:- 

x ÷ $2.75 = 6

Now lets solve for x :-
To solve for x we will use d INVERSE OPERATION of division which is multiplication. Lets do it:-

x ÷ 2.75 = 6
6 × 2.75 = x
6 × 2.75 = 16.50
x = 16.50 

CHECK OUR WORK:-

x ÷ 2.75 = 6
x = 16.50
16.50 ÷ 2.75 = 6
We were RIGHT!!

So, our equation for dis question would be x ÷ 2.75 = 6. When we solve for x, x = 16.50. Sophia can spend $16.50 on her party favors for 6 people. 

Hope I helped ya!! xD 
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The annual precipitation amounts in a certain mountain range are normally distributed with a mean of 104 inches, and a standard
dsp73

Answer:

91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 104, \sigma = 14, n = 49, s = \frac{14}{\sqrt{49}} = 2

What is the probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

This is the pvalue of Z when X = 106.8. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{106.8 - 104}{2}

Z = 1.4

Z = 1.4 has a pvalue of 0.9192

0.9192 = 91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

8 0
3 years ago
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Marysya12 [62]

Answer:

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Step-by-step explanation:

flip -3/5

4×5 / 15×-3

20/-45

÷5 ÷5

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7 0
3 years ago
What is the answer for each sentence
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Answer:

1. surface area, 2. volume. 3. surface area, 4. volume

Step-by-step explanation:

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the question is asking how many shoe boxes can fit IN

5 0
3 years ago
Urgent math help needed will mark brainliest
iren [92.7K]

Remark

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9C3 = 84. You put it into your calculator as 9   2nF   nCr 3 =

Solution

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