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zavuch27 [327]
3 years ago
9

A cotton candy vendor has 22 cones of blue cotton candy to sell. If the blue cotton candy is 50% of the total number of cones, h

ow many total cotton candy cones does he have?
Mathematics
2 answers:
Scilla [17]3 years ago
6 0
50% is another way of writing 0.50 or 1/2.

Blue cotton candy is 50%, there are 22 blues, therefore 22 is 50% of the total number.

Using algebra,
0.50x=22
X=44

Another way to think about this is simply to consider that 50% is half, and if 22 is half then one need only multiply by two to get the whole.
Feliz [49]3 years ago
4 0
44. You can come to this answer by using algebra,
1/2x = 22
Multiply both sides by 2(denominator) thus,
X = 44.
Or you can use lateral thinking and realise that if 22 is 50%, you need to multiply by 2 to reach 100%.
You might be interested in
How I divide % percent's to any number
Darina [25.2K]
The steps matter on the size of the number.
4 0
3 years ago
Read 2 more answers
Line g passes through points (5, 9) and (3, 2). Line h passes through points (9, 10) and (2, 12). Are line g and line h parallel
icang [17]

For this case we find the slopes of each of the lines:

The g line passes through the following points:

(x_ {1}, y_ {1}) :( 3,2)\\(x_ {2}, y_ {2}) :( 5,9)

So, the slope is:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {9-2} {5-3} = \frac {7} {2}

Line h passes through the following points:

(x_ {1}, y_ {1}) :( 9,10)\\(x_ {2}, y_ {2}) :( 2,12)

So, the slope is:

m = \frac {y_ {2} -y_ {1}}{x_ {2} -x_ {1}} = \frac {12-10} {2-9} = \frac {2} {- 7} = - \frac {2} {7}

By definition, if two lines are parallel then their slopes are equal. If the lines are perpendicular then the product of their slopes is -1.

It is observed that lines g and h are not parallel. We verify if they are perpendicular:

\frac {7} {2} * - \frac {2} {7} = \frac {-14} {14} = - 1

Thus, the lines are perpendicular.

Answer:

The lines are perpendicular.

8 0
3 years ago
A sample survey is designed to estimate the proportion of sports utility vehicles being driven in the state of California. A ran
mart [117]

Answer:

a) The 95% confidence interval would be given (0.070;0.121).

b) "increase the sample size n"

"decrease za/2 by decreasing the confidence"

Step-by-step explanation:

Notation and definitions

X=48 number of vehicles classified as sports utility.

n=500 random sample taken

\hat p=\frac{48}{500}=0.096 estimated proportion of vehicles classified as sports utility vehicles.

p true population proportion of vehicles classified as sports utility vehicles.

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

(a) Use a 95% confidence interval to estimate the proportion of sports utility vehicles in California. (Round your answers to three decimal places.)

The confidence interval would be given by this formula :

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.5=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

And replacing into the confidence interval formula we got:

0.096 - 1.96 \sqrt{\frac{0.096(1-0.096)}{500}}=0.070

0.096 + 1.96 \sqrt{\frac{0.096(1-0.096)}{500}}=0.121

And the 95% confidence interval would be given (0.070;0.121).

We are confident (95%) that about 7.0% to 12.1% of vehicles in California are classified as sports utility .  

(b) How can you estimate the proportion of sports utility vehicles in California with a higher degree of accuracy? (HINT: There are two answers. Select all that apply.)

For this case we just have two ways to increase the accuracy one is "increase the sample size n" since if we have a larger sample size the estimation would be more accurate. And the other possibility is "decrease za/2 by decreasing the confidence" because if we decrease the confidence level the interval would be narrower and accurate

7 0
3 years ago
!!!3 QUESTIONS!!!
RUDIKE [14]

Answer:

1.) He still owes $100 of debt

2.) 1 rose would be .75 cents and 1 carnation would be .90 cents

3.) C 8 and 3/8

Step by Step explanation

(/ means divided by in the first 2 equations but / in the last question is for the fractions.)

1.) _(1,500 / 3 =500. 1,500 - 500 =1,000 / 5 =200 x 3 =600. 700 - 600 =$100)

2.)_(1.50/2 =.75 cents. 2.70/3 =.90 cents.)

3.) i first added the fractions ( i equalized them) then i added the whole numbers (the u in the equation was to separate the whole num. and fraction )

Before i equalized it: (6u3/4 + 1u1/8 = 7u1/8 + 1/8 = 8u3/8)

After i equalized it: (6u6/8 + 1u1/8 = 7u1/8 + 1/8 = 8u3/8)

6 0
3 years ago
Solve the system using substitution:<br> y = -6x + 7<br><br> 3x – 2y = 16<br><br> helppp
bearhunter [10]

Answer:

x=-6 y=-1

Step-by-step explanation:

// Solve equation [2] for the variable  y  

 

 [2]    y = -x - 7

// Plug this in for variable  y  in equation [1]

  [1]    3x - 2•(-x -7) = -16

  [1]    5x = -30

// Solve equation [1] for the variable  x  

  [1]    5x = - 30  

  [1]    x = - 6  

// By now we know this much :

   x = -6

   y = -x-7

// Use the  x  value to solve for  y  

   y = -(-6)-7 = -1  

Solution :

{x,y} = {-6,-1}

7 0
3 years ago
Read 2 more answers
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