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musickatia [10]

3 years ago

15

Chad and Victoria are playing a game with a quarter and a spinner divided into sixths numbered one through six each player spins

a spinner and tosses a coin how many outcomes are possible in the game?

1 answer:

rodikova [14]3 years ago

8 0

The simple way to do this is to multiply the number of outcomes of one object times the number of outcomes in the other object. In this case a quarter has 2 sides, heads and tails. Since the spinner has 6 sections, there are 6 outcomes.

With this we can do, 2x6=12.

Therefore there are 12 outcomes

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Nerisa has 5 pink bow, 1 Blue bow ,and 4 Purple bows in a box. She will Randomly choose 1 bow from the box

4vir4ik [10]

The answer is A. Hope this helps

3 0

3 years ago

Solve the equation p/4+10=14

Gelneren [198K]

Answer:

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Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

Find the probability p(e or f) if e and f are mutually exclusive, p(e)equals 0.25, and p(f)equals 0.51.

Masteriza [31]

The definition of two events being mutually exclusive (or disjoint) only means that it is not possible for the two events to occur together. Given two events, E and F, they are mutually exclusive and also mean independent.

In this case, since events E and F are mutually exclusive, therefore the probability that either E or F will occur will simply be the sum of two events.

P (E or F) = P (E) + P (F)

P (E or F) = 0.25 + 0.51

P (E or F) = 0.76

Therefore this means that there is a 76% probability that either E or F will occur.

8 0

3 years ago

Robert says the expression 2+3 times 7 and 2+(3 times 7) have the same value. Is Robert correct? Explain your answer and evaluat

erastovalidia [21]

Yes because you multiply first so in this case you multiply 7 and 3 first. Since the second expression is in parenthesis you do that first just like you do 7 times 3. Then you just add 2 to that. The value of both expressions is 23

4 0

3 years ago