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Scilla [17]
2 years ago
5

Nerisa has 5 pink bow, 1 Blue bow ,and 4 Purple bows in a box. She will Randomly choose 1 bow from the box

Mathematics
1 answer:
4vir4ik [10]2 years ago
3 0
The answer is A. Hope this helps

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The height, in inches, of a randomly chosen American woman is a normal random variable with mean μ = 64 and variance 2 = 7.84. (
Schach [20]

Answer:

Step-by-step explanation:

Given that the height in  inches, of a randomly chosen American woman is a normal random variable with mean μ = 64 and variance 2 = 7.84.

X is N(64, 2.8)

Or Z = \frac{x-64}{2.8}

a)  the probability that the height of a randomly chosen woman is between 59.8 and 68.2 inches.

=P(59.8

b) P(X\geq 59)\\= P(X\geq -1.78)\\ \\=0.9625

c) For 4 women to be height 260 inches is equivalent to

4x will be normal with mean (64*4) and std dev (2.8*4)

4x is N(266, 11.2)

P(4x>260)= \\P(Z\geq -0.53571)\\=0.7054

d) Z is N(0,1)

E(Z19) = P(Z>19)\\= 0.000

since normal distribution is maximum only between 3 std deviations form the mean on either side.

3 0
3 years ago
Hi i need help below thank you 32 POINTS
lara [203]
A = (pi) * r*2
(pi) = 3.14
r = d/2.....r = 17/2 or 8.5

A = 3.14 * 8.5^2
A = 3.14 * 72.25
A = 226.86 rounds to 226.9 m^2 <==
6 0
2 years ago
Students in Mr. Hill’s class were asked how many TV shows they watched last weekend. The results are shown on the line plot.
MAXImum [283]

Answer:

D

Step-by-step explanation:

Plz mark brainliest

8 0
2 years ago
The perimeter of a rectangle is 78cm.
mestny [16]

Answer:

17 cm

Step-by-step explanation:

P=2L+2W

L=22, P=78 we want to find W

78=2(22)+2W

78=44+2W

34=2W

W=17 cm

3 0
2 years ago
The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a m
Mazyrski [523]

Answer:

The probability that the instrument does not fail in an 8-hour shift is P(X=0) \approx 0.8659

The probability of at least 1 failure in a 24-hour day is P(X\geq 1 )\approx 0.3508

Step-by-step explanation:

The probability distribution of a Poisson random variable X representing the number of successes occurring in a given time interval or a specified region of space is given by the formula:

P(X)=\frac{e^{-\mu}\mu^x}{x!}

Let X be the number of failures of a testing instrument.

We know that the mean \mu = 0.018 failures per hour.

(a) To find the probability that the instrument does not fail in an 8-hour shift, you need to:

For an 8-hour shift, the mean is \mu=8\cdot 0.018=0.144

P(X=0)=\frac{e^{-0.144}0.144^0}{0!}\\\\P(X=0) \approx 0.8659

(b) To find the probability of at least 1 failure in a 24-hour day, you need to:

For a 24-hour day, the mean is \mu=24\cdot 0.018=0.432

P(X\geq 1 )=1-P(X=0)\\\\P(X\geq 1 )=1-\frac{e^{-0.432}0.432^0}{0!}\\\\P(X\geq 1 )\approx 0.3508

3 0
3 years ago
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