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3 years ago

Quadrilateral ABCD is inscribed in a circle. Find the measure of each of the angles of the quadrilateral.

Mathematics

1 answer:

Nadusha1986 [10]3 years ago

4 0

Here is a reference to the Inscribed Quadrilateral Conjecture it says that opposite angles of an inscribed quadrilateral are supplemental.

Explanation:

The conjecture, #angleA and angleC# allows us to write the following equation:

#angleA + angleC=180^@#

Substitute the equivalent expressions in terms of x:

#x+2+ x-2 = 180^@#

#2x = 180^@#

#x = 90^@#

From this we can compute the measures of all of the angles.

#angleA=92^@#

#angleB=100^@#

#angleC=88^@#

<span>#angleD= 80^@#</span>

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Question in attachment

kiruha [24]

Answer:

1. a= 7, A = 49 degrees

Side A = 7 , Side B = 24, Side C = 25

A= 49 degrees, C = 90 degrees , B=41

2. A= 4, B = 6.9, C=8

A= 22 degrees, B = 68, C= 90

3. A= 7, B = 14.4, C=16

A= 45 , B=45 , C=90

6 0

3 years ago

Which expression is equivalent to 4^-5 • 3^-5 ?

valkas [14]

The expression equivalent to 4^-5 • 3^-5 is 12^-5

<h3>What are equivalent expressions?</h3>

Equivalent expressions are simply known as expressions with the same solution but different arrangement.

Given the index expressions;

4^-5 • 3^-5

Using the exponent rule, the two values are have different bases but the same exponent and thus, we multiply the bases and leave the exponents the same way.

This can be written as;

4(3) ^ -5

expand the bracket

12^-5

Thus, the expression equivalent to 4^-5 • 3^-5 is 12^-5

Learn more about equivalent expressions here:

brainly.com/question/24734894

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7 0

2 years ago

Beaker A contains 1 liter which is 30 percent oil and the rest is vinegar, thoroughly mixed up. Beaker B contains 2 liters which

alekssr [168]

Answer:

1.25 liters of oil

Step-by-step explanation:

Volume in Beaker A = 1 L

Volume of Oil in Beaker A = 1*0.3 = 0.3 L

Volume of Vinegar in Beaker A = 1*0.7 = 0.7 L

Volume in Beaker B = 2 L

Volume of Oil in Beaker B = 2*0.4 = 0.8 L

Volume of Vinegar in Beaker B = 1*0.6 = 1.2 L

If half of the contents of B are poured into A and assuming a homogeneous mixture, the new volumes of oil (Voa) and vinegar (Vva) in beaker A are:

$V_{oa} = 0.3+\frac{0.8}{2} \\V_{oa} = 0.7 \\V_{va} = 0.7+\frac{1.2}{2} \\V_{va} = 1.3$

The amount of oil needed to be added to beaker A in order to produce a mixture which is 60 percent oil (Vomix) is given by:

$0.6*V_{total} = V_{oa} +V_{omix}\\0.6*(V_{va}+V_{oa} +V_{omix}) = V_{oa} +V_{omix}\\0.6*(1.3+0.7+V_{omix})=0.7+V_{omix}\\V_{omix}=\frac{0.5}{0.4} \\V_{omix}=1.25 \ L$

1.25 liters of oil are needed.

6 0

3 years ago

What is the equation of the following line? (-3,9)(0,0)

lana [24]

<span>(-3,9)(0,0)
slope = 9 / -3 = -3
b = 0

equation
y = -3x</span>

3 0

3 years ago

Read 2 more answers

Find the sum or difference of (2m+7)-(3-4m)

pickupchik [31]

(2m + 7) - (3 - 4m)

First distribute the (-) in front of the quantity of 3 - 4m.
Think of it as this:

-1(3 - 4m)

You multiply each number inside the parenthesis by -1.

So:

3*-1 = -3
-4m * -1 = 4m

Now that you've distributed the negative you can remove the parenthesis.
Now you'll just set it all up like you would any normal problem. Because -3 is negative you'll make it subtract.... I'll show you what I mean:

2m + 7 - 3 + 4m

Combine like terms (Terms which have the same variables... in this case the same number of m's)

Rearranging them can help!

4m + 2m + 7 - 3

6m + 7 - 3

6m + 4, is our difference!

6 0

3 years ago

Read 2 more answers