assume you want a line that goes through the given point and parallel to the given line. A line that is parallel to y=2/3 x + 5 will have the same slope. slope of that line is 2/3...the number in front of the x. So our new line will have slope of 2/3. now we need the y-intercept. To find that start with a slope intercept equation y=mx+b plug in the slope that we already know...it goes in for x...will be the number in front of x y= 2/3 x + b. now all we need is a number to plug in for the "b" and we will have it. to get the "b"...start with the part you already know. y = 2/3 x + b use the point they gave you...(-3,1)...and get x and y from it x will be -3 and y will be 1 plug that in 1= 2/3 ( -3) + b now we solve for b 1 = -2 + b 3 = b now we have the b we need y = 2/3 x + b y = 2/3 x + 3
Answer:
false
Step-by-step explanation:
consider y = 3
its 6 for one and 3 for the other
Answer:
C
Step-by-step explanation:
The answer is 20 because five times four is 20 so all you do is multiple
We have that
<span>y=1/2x-3
1) the slope of this line equation is m=(1/2)
2) the coordinates of the y intercept are
for x=0
y=-3
point (0,-3)
3)</span>the coordinates of the x intercept are
for y=0
0=(1/2)x-3------> (1/2)x=3----> x=6
point (6,0)
<span>if the line is dilated by a factor of 3
then
</span>y=1/2x-3--------> 3y=3*[1/2x-3]-----> 3y=(3/2)x-9
3y=(3x-18)/2-------> y=(3x-18)/6--------> y=(3/6)x-18/6
y=(3/6)x-18/6
so
1) the slope of this line equation is m=(3/6)-----> 3/6=1/2
2) the coordinates of the y intercept are
for x=0
y=-18/6-------> y=-3
point (0,-3)
3)the coordinates of the x intercept are
for y=0
0=(3/6)x-18/6------> (3/6)x=18/6----> x=18/3------> x=6
point (6,0)
therefore
the equation of the line
y=1/2x-3 is the same that the equation of the line y=(3/6)x-18/6
<span>the equation does not change because the slope and the x and y intercepts do not change either</span>