Ask question

Ask question

All categories

3 years ago

11

You have been averaging 55 sales per day. Per our new policy, everyone needs to increase his or her sales per day by 10% in the

next month. Rounding up, by next month you will need to be up to __________ sales.

1 answer:

Mariulka [41]3 years ago

8 0

To find your new number of sales per month, you will need to find the number of sales you have per month (based on 30 days per month).

55 x 20 = 1650 sales.

Than, you will need to calculate what 10% of this is and add it to your original sales number.

0.1 (10%) x 1650 = 165

1650 + 165 = 1815

You will need approximately 1815 sales based on the 30 day month.

You might be interested in

Find the function y1 of t which is the solution of 121y′′+110y′−24y=0 with initial conditions y1(0)=1,y′1(0)=0. y1= Note: y1 is

strojnjashka [21]

Answer:

Step-by-step explanation:

The original equation is $121y''+110y'-24y=0$ . We propose that the solution of this equations is of the form $y = Ae^{rt}$ . Then, by replacing the derivatives we get the following

$121r^2Ae^{rt}+110rAe^{rt}-24Ae^{rt}=0= Ae^{rt}(121r^2+110r-24)$

Since we want a non trival solution, it must happen that A is different from zero. Also, the exponential function is always positive, then it must happen that

$121r^2+110r-24=0$

Recall that the roots of a polynomial of the form $ax^2+bx+c$ are given by the formula

$x = \frac{-b \pm \sqrt[]{b^2-4ac}}{2a}$

In our case a = 121, b = 110 and c = -24. Using the formula we get the solutions

$r_1 = -\frac{12}{11}$

$r_2 = \frac{2}{11}$

So, in this case, the general solution is $y = c_1 e^{\frac{-12t}{11}} + c_2 e^{\frac{2t}{11}}$

a) In the first case, we are given that y(0) = 1 and y'(0) = 0. By differentiating the general solution and replacing t by 0 we get the equations

$c_1 + c_2 = 1$

$c_1\frac{-12}{11} + c_2\frac{2}{11} = 0$ (or equivalently $c_2 = 6c_1$

By replacing the second equation in the first one, we get $7c_1 = 1$ which implies that $c_1 = \frac{1}{7}, c_2 = \frac{6}{7}$ .

So $y_1 = \frac{1}{7}e^{\frac{-12t}{11}} + \frac{6}{7}e^{\frac{2t}{11}}$

b) By using y(0) =0 and y'(0)=1 we get the equations

$c_1+c_2 =0$

$c_1\frac{-12}{11} + c_2\frac{2}{11} = 1$ (or equivalently $-12c_1+2c_2 = 11$

By solving this system, the solution is $c_1 = \frac{-11}{14}, c_2 = \frac{11}{14}$

Then $y_2 = \frac{-11}{14}e^{\frac{-12t}{11}} + \frac{11}{14} e^{\frac{2t}{11}}$

c)

The Wronskian of the solutions is calculated as the determinant of the following matrix

$\left| \begin{matrix}y_1 & y_2 \\ y_1' & y_2'\end{matrix}\right|= W(t) = y_1\cdot y_2'-y_1'y_2$

By plugging the values of $y_1$ and

We can check this by using Abel's theorem. Given a second degree differential equation of the form y''+p(x)y'+q(x)y the wronskian is given by

$e^{\int -p(x) dx}$

In this case, by dividing the equation by 121 we get that p(x) = 10/11. So the wronskian is

$e^{\int -\frac{10}{11} dx} = e^{\frac{-10x}{11}}$

Note that this function is always positive, and thus, never zero. So $y_1, y_2$ is a fundamental set of solutions.

8 0

3 years ago

Ryan conducted a 6-day study observing the effects of an organic plant food on the growth of his sprouting bean plant. He tracke

Artemon [7]

Answer:

B: This relationship is not a function because more than one amount of plant food remains each day

Step-by-step explanation:

It is given that Ryan did an experiment by observing the effects of plant food and the growth of the sprouting bean plant. He made a note of the height of the bean plant and the amount of food remaining in the container for the plant after feeding each day.

Thus he observed that the plant food in the container decreases by an equal amount everyday as the bean plant grew. Thus this states that it is not a function between the two as there are more than one plant food remaining each day for the plant.

A relationship is a function when one element belongs to one thing.

4 0

3 years ago

Solve the inequality <br> r/6 < or equal to 3

RSB [31]

R is greater then or equal to18

6 0

3 years ago

Please help me with my math homework what is the answer!!!

Dmitry [639]

Answer:

Step-by-step explanation:

The letters are easy enough.

y^3 determines that 3 ys are needed. y^2 is taken in by the cubed.

x^4 determines that 4 xs are needed. x^3 is part of x^4 and you don't need any more xs

12 and 42 are the parts that will cause the problem. Factor them both into prime factors

12: 2 * 2 * 3

42: 2 * 3 * 7

You need two 2s.

You need one 3

You need one 7

LCD = 2 *2*3 * 7 = 84

6 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bp%7D%7B%20-%208%7D%20%20%2B%209%20%3E%2013" id="TexFormula1" title=" \frac{p}{ -

Gnom [1K]

is the answer open circle?

7 0

3 years ago

Read 2 more answers