Answer:
The feasible region in the attached figure
Step-by-step explanation:
Let
x ----> the number of shirts
y ----> the number of pants
we know that
The cost of the shirts (number of shirts multiplied by the cost of one shirt) plus the cost of the pants (number of pants multiplied by the cost of one pant) must be less than or equal to $80
so
The inequality that represent this problem is
using a graphing tool
The feasible region is the triangular shaded area
see the attached figure
Answer:
7 9/10
Step-by-step explanation:
cuz mah brain big
Answer: £11.69
Explanation:
1) Work out 2% of £1600:
1600 x 2/100 =36
2) Add it on to the original number to get his new monthly pay:
1600 + 36 = £1636
3) Work out his yearly pay by:
a) finding the amount of months he worked:
46 / 4 = 11.5 months
b) Divide 11.5 into 2 bits and add them on:
1636 x 11 = 17997
1636 x 0.5 = 818
17997 + 818 = £18814
4) To get his pay per week:
18814 / 46 = £409
5) Finally, to get his pay per hour:
409 / 35 = 11.68671...
= £ 11.69
Answer:
Step-by-step explanation:
Simplifying
3.4 + 2(9.7 + -4.8x) = 61.2
3.4 + (9.7 * 2 + -4.8x * 2) = 61.2
3.4 + (19.4 + -9.6x) = 61.2
Combine like terms: 3.4 + 19.4 = 22.8
22.8 + -9.6x = 61.2
Solving
22.8 + -9.6x = 61.2
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-22.8' to each side of the equation.
22.8 + -22.8 + -9.6x = 61.2 + -22.8
Combine like terms: 22.8 + -22.8 = 0.0
0.0 + -9.6x = 61.2 + -22.8
-9.6x = 61.2 + -22.8
Combine like terms: 61.2 + -22.8 = 38.4
-9.6x = 38.4
Divide each side by '-9.6'.
x = -4
Simplifying
x = -4
