The load that the same type of beam can support is 583.345 pounds if its width is 3.5 inches.
As the maximum load that can be carried by the beam is directly proportional to the width of the beam and a 1.5 inches wide beam can support a load of 250 pounds, an equation can be written as;
L = kw
Here L represents the maximum load supported and w represents the width and k is the constant of proportionality. Therefore;
250 = k × 1.5
Solving for k;
k = 250 ÷ 1.5
k = 166.67
Therefore the equation can be written as;
L = 166.67 w
As the width of the same type of beam is 3.5 inches, the maximum load it can support can be calculated as follows;
L = 166.67 × 3.5
L = 583.345 pounds
Therefore; 583.345 pounds is the maximum load that the beam can support if its width is 3.5 inches.
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Answer:
The volume of water needed to be removed = 4301100 lbs/ [ 62.43 × 27] = 2551.66.
Explanation:
The first thing to do right now is to determine the weight of soil solids. This can be gotten below as:
The weight of soil solids = 1 × 118 × 27 = <em>3186 lbs. </em>
Also, there is the need to determine the value of the water that we have and the one that is needed. This is calculated below as:
The weight of water needed = 3186 × 6% = 191.16 lbs.
The water available = 3186 × 7% = 223.02%.
The next thing to determine is the value for the total BCY of available of soil.
Thus, the total BCY of available of soil = [ 3186 + 223.02 ]/ 2800 × 135000 = 3409.02/ 2800 = 1.217551 BCY × 135000 = 164,363.46 BCY.
The last thing to do here is to determine the value for the weight and volume of water to be removed.
The weight of water to be removed = [ 223.02 lbs - 191.16 lbs] × 135,000 = 4301100 lbs
The volume of water needed to be removed = 4301100 lbs/ [ 62.43 × 27] = 2551.66.
Answer:
Explanation along with code and output results is provided below.
C++ Code:
#include <iostream>
using namespace std;
int main()
{
int year;
cout<<"Enter the car model year."<<endl;
cin>>year;
if (year<=1969)
{
cout<<"Few safety features."<<endl;
}
else if (year>=1970 && year<1989)
{
cout<<"Probably has seat belts."<<endl;
}
else if (year>=1990 && year<1999)
{
cout<<"Probably has antilock brakes."<<endl;
}
else if (year>=2000)
{
cout<<"Probably has airbags."<<endl;
}
return 0;
}
Explanation:
The problem was to print feature messages of a car given its model year.
If else conditions are being used incorporate the logic. The code has been tested with several inputs and got correct output results.
Output:
Enter the car model year.
1961
Few safety features.
Enter the car model year.
1975
Probably has seat belts.
Enter the car model year.
1994
Probably has antilock brakes.
Enter the car model year.
2005
Probably has airbags.
Nyatakan fungsi bagi pisau-pisau yang ditunjukkan dalam rajah di atas: good.
Anything else: bad.