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Firlakuza [10]
3 years ago
9

If water molecules pass through a membrane with a steady state flux of 220 mole/(m2 day), how long will it take, in hours, for 0

.400 kg of water to pass through a 565 square centimeter of the membrane?
Engineering
1 answer:
goblinko [34]3 years ago
7 0

Answer:

<em>0.0386 hr</em>

<em></em>

Explanation:

Area = 565 cm^2 = 0.0565 m^2  (1 cm^2 = 0.0001 m^2)

flux state rate = 220 mole/m^2-day

<em>There are 24 hrs in a day,</em> therefore rate in hrs will be

220/24 = 9.17 mole/m^2-hr

mass of water = 0.4 kg

molar mass of water = (1 x 2) + 16 = 18 kg/mole

therefore,

<em>mole of water = mass of water/molar mass of water</em>

mole of water = 0.4/18 = 0.02 mole

<em>mole flux = mole/area</em> = 0.02/0.0565 = 0.354 mol/m^2

<em>time that will be taken will be for water to pass = mole flux/mole flux rate</em>

time = 0.354/9.17 = <em>0.0386 hr</em>

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Answer:

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Explanation:

Hi!

To solve follow the steps below!

1. Find the density of the air at the entrance using the equation for ideal gases

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2.find the mass flow by finding the product between the flow rate and the density

m=(density)(flow rate)

flow rate=10L/s=0.01m^3/s

m=(1.43kg/m^3)(0.01m^3/s)=0.0143kg/s

3. Please use the equation the first law of thermodynamics that states that the energy that enters is the same as the one that must come out, we infer the following equation, note = remember that power is the product of work and mass flow

Work

w=Cp(T1-T2)

Where

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w=work

T1=inlet temperature=20C

T2=outlet temperature=300C

w=1.005(300-20)=281.4KJ/kg

Power

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5 0
3 years ago
What are typical uses of Mainframe computer?​
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7 0
3 years ago
A single-degree-of-freedom mass-spring-damper system is observed during its free vibration and the displacement amplitude decays
AleksandrR [38]

Answer:

Logarithmic decrement is equal to 0.182

Explanation:

given,

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number of cycles = 12 cycles        

mass of the system = 7 kg        

spring stiffness = 3000 N/m            

logarithmic decrement = ?                  

now,                                                      

logarithmic decreament = ln\ D^{\frac{1}{n}}

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Hence, Logarithmic decrement is equal to 0.182

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4 years ago
LAB 3.3 – Working with String Input and Type CastingStep 1: RemovefindErrors.cppfrom the project and add thepercentage.cppprogra
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Answer:

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