Explanation:
I think it would be C but i dont know because i dont have the following question
Answer:
Q=0.00274 Lt/s
Explanation:
Given that
Darcy friction factor f=0.04
Diameter of pipe d=10 mm
We know that for laminar flow
Where Re is the Reynolds number and f is the friction factor.
Now by putting the values
Re=400
We know that
for water
V=0.035 m/s
So volume flow rate Q=AV
Q=0.00274 Lt/s
Answer:
class helloSarah {
public static void main(String [] args) {
Name = "Hello Sarah";
System.out.print(Name);
}
}
Explanation:
<em>The question seem incomplete; However, since the program is incorrect, I'll assume the question is to correct the given code;</em>
The program segment was written in Java and the correct program is in the answer section
<u>See bold texts for line by line explanation </u>
This line declares the class name
<em>class helloSarah {</em>
This line declares the main method of the program
<em>public static void main(String [] args) {</em>
This line initializes string variable Name
<em>String Name = "Hello Sarah";</em>
This line prints the initialized variable
<em>System.out.print(Name);</em>
<em>}</em>
<em>}</em>
<em />
Answer:
I. 3.316 kW
II. 1.218 kW
III. 2.72
Explanation:
At state 1, the enthalpy and entropy are determined using the given data from A-13.
At P1 = 200kpa and T1 = 0,
h1 = 253.07 kJ/kg
s1 = 0.9699 kJ/kgK
At state 2, the isentropic enthalpy is determined at P2 = 1400kpa and s1 = s2 by interpolation. Thus
h2(s) = 295.95 kJ/kg
The actual enthalpy is then gotten by
h2 = h1 + [h2(s) - h1]/n
h2 = 253.07 + [295.95 - 253.07]/0.88
h2 = 253.07 + 48.73
h2 = 301.8 kJ/kg
h3 = h4 = 120.43 kJ/kg
Heating load is determined from energy balance, thus,
Q'l = m'(h1 - h4)
Q'l = 0.025(253.07 - 120.43)
Q'l = 0.025 * 132.64
Q'l = 3.316 kW
Power is determined by using
W' = m'(h2 - h1)
W'= 0.025(301.8 - 253.07)
W'= 0.025 * 48.73
W'= 1.218 kW
The Coefficient Of Performance is Q'l / W'
COP = 3.316/1.218
COP = 2.72
Answer:
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