Question

In order to properly construct this road you have determined that you need to bring in 135,000 CCY of fill material to construct the sub-base. The fill material that is available is dry earth, with a weight of 2800 lbs/BCY and a moisture content of 7%. The percent swell for this soil is 25%. The final compaction level will be 118 PCF dry density and the optimum moisture content is 6%. How many BCY of earth must be excavated to meet this requirement

Answer 1

Answer:

The volume of water needed to be removed = 4301100 lbs/ [ 62.43 × 27] = 2551.66.

Explanation:

The first thing to do right now is to determine the weight of soil solids. This can be gotten below as:

The weight of soil solids = 1 × 118 × 27 = 3186 lbs.

Also, there is the need to determine the value of the water that we have and the one that is needed. This is calculated below as:

The weight of water needed = 3186 × 6% = 191.16 lbs.

The water available = 3186 × 7% = 223.02%.

The next thing to determine is the value for the total BCY of available of soil.

Thus, the total BCY of available of soil = [ 3186 + 223.02 ]/ 2800 × 135000 = 3409.02/ 2800 = 1.217551 BCY × 135000 = 164,363.46 BCY.

The last thing to do here is to determine the value for the weight and  volume of water to be removed.

The weight of water to be removed = [ 223.02 lbs -  191.16 lbs] × 135,000 = 4301100 lbs

The volume of water needed to be removed = 4301100 lbs/ [ 62.43 × 27] = 2551.66.