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3 years ago

A right cylinder has a radius of 3 and a height of 12. what is its surface area?

Mathematics

2 answers:

tester [92]3 years ago

8 0

The surface area is 90pi

Katarina [22]3 years ago

3 0

Answer:

Surface area of cylinder = 282 .6 square units.

Step-by-step explanation:

Given : A right cylinder has a radius of 3 and a height of 12.

To find : what is its surface area

Solution : We have given that radius = 3

Height = 12.

Surface area of cylinder = 2πr ( r +h)

Surface area of cylinder = 2 *3.14 * 3 ( 3 +12)

= 18.84 (15)

Surface area of cylinder = 282 .6 square units.

Therefore, Surface area of cylinder = 282 .6 square units.

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Sekhar gives a quarter of his sweets to Renu and then gives 5 sweets to Raji. He has

Feliz [49]

Answer:

16 sweets

Step-by-step explanation:

Number of sweet that Sekhar had = x

Sweets given to Renu = (1/4) of x = $\frac{1}{4}x$

Sweets given to Raji = 5

Remaining sweets = 7

$x = \frac{1}{4}x +5 + 7\\\\x -\frac{1}{4}x = 12\\\\\frac{4*x}{1*4}x-\frac{1}{4}x = 12\\\\\frac{4x}{4}-\frac{1}{4}x= 12\\\\\frac{3x}{4}=12\\\\x = 12*\frac{4}{3}\\\\x=4*4\\\\x=16$

6 0

2 years ago

Given the following function, find f(-2), f(0), and f(4).

borishaifa [10]

Answer:

f(-2) = 0

f(0) = -4

f(4) = 12

Step-by-step explanation:

Given the function f(x) = x^2 - 4, we must plug in the values substituting x for each of the answers.

f(-2) = (-2)^2 - 4

-2 times itself is a positive 4, therefore:

f(-2) = 4 - 4

f(-2) = 0

We do the same for each answer.

f(0) = (0)^2 - 4

f(0) = -4

f(4) = (4)^2 - 4

f(4) = 16 - 4

f(4) = 12

6 0

3 years ago

Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 72.6 Mbp

Lapatulllka [165]

Answer:

a. 54.05 Mpbs.

b. 2.745... standard deviations.

c. The z-score is 2.745....

d. The carrier's highest data speed is significantly high.

Step-by-step explanation:

a. The difference between the highest measured data speed and the mean is 72.6 - 18.55 = 54.05 Mbps.

b. The amount of standard deviations of 54.05 Mbps is equal to this value divided by the standard deviations, so we yield $\frac{54.05}{19.69} = 2.745...$ standard deviations.