LM has the endpoints L at –5 and M at 9. To find the point x so that x divides the directed line segment LM in a 2:3 ratio, use
2 answers:
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Answer:
The basis is <1/√3, -2/5 x + 1 /15, 0.4825x^2 - 0.6466 x -0.3748>
Step-by-step explanation:
First, we calculate the norm of f
||f||² = <f,f> = f(-1)²+f(0)²+f(1)² ) = 3*(-7)² = 147
Therefore, ||f|| = √147
We take as the first element of the basis
we define
lets calculate <g,v1>
g(-1) = 9
g(0) = 5
g(1) = 1
v1(-1) = v1(0) = v1(1) = 1/√3
Then <g,v1> = 9*7/√(147)+5*7/√(147)+1*7/√(147) = 15*7/√(147) = 105/√147
and <g,v1>v1 = 105/√(147) * 7/√(147) = 735/147 = 35/9
Therefore,
Now, lets calculate the norm, for that
As a result,
We take
Finally, we take
Note that
h(-1) = 7
h(0) = -5
h(1) = -9
v1(-1) = v1(0) = v1(1) = 7/√(147) = 1/√3
v2(-1) = 7/15
v2(0) = 1/15
v3(1) = -1/3
Thus,
<h,v1>v1 = (7-5-9)*(7/√(147))² = -7/3
<h,v2>v2 = ((7*7/15) + (-5*1/15) + (-9*-1/3)) * (-2/5 x + 1 /15) = -66/25 x + 11/25
As a consecuence, we have that
since
we obtain that
Therefore,
The basis is <1/√3, -2/5 x + 1 /15, 0.4825x^2 - 0.6466 x -0.3748>