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NeX [460]
3 years ago
9

LM has the endpoints L at –5 and M at 9. To find the point x so that x divides the directed line segment LM in a 2:3 ratio, use

the formula x = (x2 – x1) + x1.
x = (9 – (–5)) + (–5)
Mathematics
2 answers:
sdas [7]3 years ago
5 0

Answer:

The value of point x is \frac{3}{5}.

Step-by-step explanation:

It is given that LM has the endpoints L at –5 and M at 9.

The point x divides the directed line segment LM in a 2:3 ratio.

The given formula is

x=\frac{m}{m+n}(x_2-x_1)+x_1

Using above formula we get

x=\frac{2}{2+3}(9-(-5))+(-5)

x=\frac{2}{5}(9+5)-5

x=\frac{2}{5}(14)-5

x=\frac{28}{5}-5

x=\frac{28-25}{5}

x=\frac{3}{5}

Therefore the value of point x is \frac{3}{5}.

Sedaia [141]3 years ago
4 0

Answer:

to be exact put it like this

3/5

Step-by-step explanation:

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6.359*10^-^1^4

Standard form:

-6.359*10^-^1^4

Since the exponent of the scientific notation is negative −14, move the decimal point 14 places to the left. 0.00000000000006359.

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Find UV (Pic Stated Below)
natta225 [31]

Answer:

UV=29

Step-by-step explanation:

In right triangles AQB and AVB,

∠AQB = ∠AVB ...(i)  {Right angles}

∠QBA = ∠VBA ...(ii)  {Given that they are equal}

We know that sum of all three angles in a triangle is equal to 180 degree. So wee can write sum equation for each triangle


∠AQB+∠QBA+∠BAQ=180 ...(iii)

∠AVB+∠VBA+∠BAV=180 ...(iv)


using (iii) and (iv)

∠AQB+∠QBA+∠BAQ=∠AVB+∠VBA+∠BAV

∠AVB+∠VBA+∠BAQ=∠AVB+∠VBA+∠BAV  (using (i) and (ii))

∠BAQ=∠BAV...(v)


Now consider triangles AQB and AVB;

∠BAQ=∠BAV  {from (v)}

∠QBA = ∠VBA {from (ii)}

AB=AB  {common side}

So using ASA, triangles AQB and AVB are congruent.

We know that corresponding sides of congruent triangles are equal.

Hence

AQ=AV

5x+9=7x+1

9-1=7x-5x

8=2x

divide both sides by 2

4=x

Now plug value of x=4 into UV=7x+1

UV=7*4+1=28+1=29

<u>Hence UV=29 is final answer.</u>

7 0
3 years ago
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8 0
3 years ago
10 POINTS PLEASE HELP
Llana [10]

Answer:

A company sells tents in two styles, shown below.

The sides and floor of each tent made of nylon.

For tunnel tent:

In a composite figure of tunnel tent :

There are two semi circle, half cylindrical shape and its base is made of Square.

Area of semi-circle is given by:

where r is the radius the circle.

Here, Diameter(d) = 8 feet

We know that: Diameter(d) = 2 r

then;

8 = 2r

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Area of square =

then;

Area of square =  square ft

Lateral surface area of cylinder =  where r is the radius and h is the height

Here, h = 8 ft

Lateral surface area of half cylinder =  square ft

Total Surface area of tunnel tent(S)=2(Area of semi-circle)+(Lateral surface area of half cylindrical)+(Area of square)

Substitute the given values we have;

square ft.

For Pup tent:

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In a figure of Pup tent:

There are 3 square shape and two triangle.

Area of square =

then;

Area of square =  square ft

Area of a triangle is given by:

Each side of a triangle is same.

This is an equilateral triangle, and its height is given by:

then;

Area of triangle = square ft.

Substitute the given values we have;

Total surface area of Pup tent(S')

=  square ft.

⇒S' > S

therefore, the tunnel tent require less nylon to manufacture.

<h2 /><h2>PLZ GIMME BRAINLIEST :)) !!!!!!</h2>

6 0
3 years ago
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