Question

43 base five to base seven

Answer 1

First convert to decimal:

$43_5=4\cdot5^1+3\cdot5^0=20+3=23$

Now convert this to base 7:

$\dfrac{23}7=3+\dfrac27$
$\dfrac27=0+\dfrac27$
$\implies23=43_5=32_7$