Question

A standard deck of 52 playing cards contains 13 cards in each of four suits: hearts, diamonds, clubs, and spades.

Answer 1

Answer:   a) 1%

Step-by-step explanation:

1st draw and 2nd draw and 3rd draw and 4th draw

   $\dfrac{13}{52}$         x         $\dfrac{12}{51}$          x         $\dfrac{11}{50}$         x        $\dfrac{39}{49}$      =     $\dfrac{66,924}{6,497,400}$

= 0.01

= 1%

Answer 2

Answer:

The odds are about 1%

Step-by-step explanation:

In order to find this, start by determining the likelihood of drawing a diamond on the first draw.

13/52

Next subtract one from each of those numbers to get the likelihood of drawing one again (since we removed one on the first draw).

12/51

Next do this a third time, subtracting one from both numbers.

11/50

Finally, use the opposite for the last draw since we want it to not be a diamond.

39/49

Now, to get the probability, multiply them all together.

13/52 * 12/51 * 11/50 * 39/49 = .01 = 1%