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Brrunno [24]
2 years ago
14

The mass of the part of a metal rod that lies between its left end and a point x meters to the right is 3x^2 kg. Find the linear

density when is 1 m, Where is the density the highest? The lowest?
Mathematics
1 answer:
Sav [38]2 years ago
4 0

Answer:

6 kg/m

Step-by-step explanation:

mass m = 3x^2.

rho ρ= dm/dx =6x

ρ(1) =6 Kg/m

linear density is the derivative of mass (m)  with respect to position(x)

that is how fast is the mass changing at that position.

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You are designing a rectangular garden. the garden will be enclosed by fencing on three sides and by a house on the fourth side.
RUDIKE [14]
Suppose the dimensions of the rectangle is x by y and let the side enclosed by a house be one of the sides measuring x, then the sides that is to be enclosed are two sides measuring y and one side measuring x.

Thus, the length of fencing needed is given by

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Substituting for y into the equation for the length of fencing needed, we have

P=x+2\left( \frac{288}{x} \right)=x+ \frac{576}{x}

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\frac{dP}{dx} =0 \\  \\ \Rightarrow1- \frac{576}{x^2} =0 \\  \\ \Rightarrow \frac{576}{x^2} =1 \\  \\ \Rightarrow x^2=576 \\  \\ \Rightarrow x=\sqrt{576}=24

Now, recall that

y= \frac{288}{x} = \frac{288}{24} =12

Thus, the length of fencing needed is given by

P = x + 2y = 24 + 2(12) = 24 + 24 = 48.

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