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trapecia [35]
4 years ago
13

Nick and Matt want to compare the size of their square computer screens. The only information they know is that Nick's computer

screen contains 409,600 pixels and Matt's computer screen contains 640,000. If both computers display images at about 80 pixels per inch, how many inches wider is Matt's computer screen?
Mathematics
1 answer:
Tom [10]4 years ago
4 0
To answer this you will use the unit rate of 80 pixels per square inch with each of the the pixels given.  So, for example, Nick's computer contains 409600 pixels, so to find the number of square inches for his screen divide the total number of pixels by 80.  This will give you a number of inches for his computer screen (409600/80=5120 inches).  For Matt, you will divide 640000 by 80 and get 8000 inches.  To find the answer subtract 8000 and 5120 to get 2880 inches.  This answer is not really reasonable for the width of the computer screen, but based on the info, this is how you find the answer.
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Answer:

1.   <u>Cost per customer</u>:  10 + x

     <u>Average number of customers</u>:  16 - 2x

\textsf{2.} \quad  -2x^2-4x+160\geq 130

3.    $10, $11, $12 and $13

Step-by-step explanation:

<u>Given information</u>:

  • $10 = cost of buffet per customer
  • 16 customers choose the buffet per hour
  • Every $1 increase in the cost of the buffet = loss of 2 customers per hour
  • $130 = minimum revenue needed per hour

Let x = the number of $1 increases in the cost of the buffet

<u>Part 1</u>

<u></u>

<u>Cost per customer</u>:  10 + x

<u>Average number of customers</u>:  16 - 2x

<u>Part 2</u>

The cost per customer multiplied by the number of customers needs to be <u>at least</u> $130.  Therefore, we can use the expressions found in part 1 to write the <u>inequality</u>:

(10 + x)(16 - 2x)\geq  130

\implies 160-20x+16x-2x^2\geq 130

\implies -2x^2-4x+160\geq 130

<u>Part 3</u>

To determine the possible buffet prices that Noah could charge and still maintain the restaurant owner's revenue requirements, solve the inequality:

\implies -2x^2-4x+160\geq 130

\implies -2x^2-4x+30\geq 0

\implies -2(x^2+2x-15)\geq 0

\implies x^2+2x-15\leq  0

\implies (x-3)(x+5)\leq  0

Find the roots by equating to zero:

\implies (x-3)(x+5)=0

x-3=0 \implies x=3

x+5=0 \implies x=-5

Therefore, the roots are x = 3 and x = -5.

<u>Test the roots</u> by choosing a value between the roots and substituting it into the original inequality:

\textsf{At }x=2: \quad -2(2)^2-4(2)+160=144

As 144 ≥ 130, the <u>solution</u> to the inequality is <u>between the roots</u>:  

-5 ≤ x ≤ 3

To find the range of possible buffet prices Noah could charge and still maintain a minimum revenue of $130, substitute x = 0 and x = 3 into the expression for "cost per customer.  

[Please note that we cannot use the negative values of the possible values of x since the question only tells us information about the change in average customers per hour considering an <em>increase </em>in cost.  It does not confirm that if the cost is reduced (less than $10) the number of customers <em>increases </em>per hour.]

<u>Cost per customer</u>:  

x =0 \implies 10 + 0=\$10

x=3 \implies 10+3=\$13

Therefore, the possible buffet prices Noah could charge are:

$10, $11, $12 and $13.

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2 years ago
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Answer:

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In the matrix equation below, what are the values of x and y?
enot [183]

Answer:

x=5,y=2

Step-by-step explanation:

The given matrix equation is

\frac{1}{2} \left[\begin{array}{cc}4&8\\x+3&-4\end{array}\right] -3\left[\begin{array}{cc}1&y+1\\-1&-2\end{array}\right]=\left[\begin{array}{cc}-1&-5\\7&4\end{array}\right]

We multiply the scalars to get;

\left[\begin{array}{cc}2&4\\ \frac{x+3}{2}&-2\end{array}\right] --\left[\begin{array}{cc}3&3y+3\\-3&-6\end{array}\right]=\left[\begin{array}{cc}-1&-5\\7&4\end{array}\right]

We simplify the right hand side to get;

\left[\begin{array}{cc}-1&1-3y\\ \frac{x+3}{2}+3&4\end{array}\right] =\left[\begin{array}{cc}-1&-5\\7&4\end{array}\right]

The two matrices are equal. This means the corresponding entries are also equal.

\Rightarrow 1-3y=-5

\Rightarrow -3y=-5-1

\Rightarrow -3y=-6

\Rightarrow y=2

Also

\frac{x+3}{2}+3=7

\Rightarrow \frac{x+3}{2}=7-3

\Rightarrow \frac{x+3}{2}=4

\Rightarrow x+3=8

\Rightarrow x=8-3

\Rightarrow x=5

4 0
4 years ago
Read 2 more answers
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