<span>C) Ro 270 degree (anticlockwise)
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</span>
92% of 30 is 27.6 and 48% of 75 is 36, so 27.6<36
the center is at the origin of a coordinate system and the foci are on the y-axis, then the foci are symmetric about the origin.
The hyperbola focus F1 is 46 feet above the vertex of the parabola and the hyperbola focus F2 is 6 ft above the parabola's vertex. Then the distance F1F2 is 46-6=40 ft.
In terms of hyperbola, F1F2=2c, c=20.
The vertex of the hyperba is 2 ft below focus F1, then in terms of hyperbola c-a=2 and a=c-2=18 ft.
Use formula c^2=a^2+b^2c
2
=a
2
+b
2
to find b:
\begin{gathered} (20)^2=(18)^2+b^2,\\ b^2=400-324=76 \end{gathered}
(20)
2
=(18)
2
+b
2
,
b
2
=400−324=76
.
The branches of hyperbola go in y-direction, so the equation of hyperbola is
\dfrac{y^2}{b^2}- \dfrac{x^2}{a^2}=1
b
2
y
2
−
a
2
x
2
=1 .
Substitute a and b:
\dfrac{y^2}{76}- \dfrac{x^2}{324}=1
76
y
2
−
324
x
2
=1 .
Answer:
(x+9)^2+(y+5)^2=81
Step-by-step explanation:
(x-h)^2+(y-k)^2=r^2
(h,k)=center
r=radius
so if you just insert the center (-9,-5) and the r with 9
(x-(-9))^2+(y-(-5))^2=9^2
(x+9)^2+(y+5)^2=81
Hope that helps :)
Answer 0.24. i hope this is right
