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Aleks04 [339]
2 years ago
11

Jakaya says the probability the marble is blue is 12/4. Adsila says 12/4 is impossible. which girl is correct.

Mathematics
1 answer:
solmaris [256]2 years ago
6 0
Adsila I checked with a friend
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Find the missing side measure.
STatiana [176]

Answer:

7 for my answer

Step-by-step explanation:

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7 0
2 years ago
The perimeter of a triangle is 47 feet. One side of the triangle is one foot longer than the second side. The third side is four
Ugo [173]

Answer:

The lengths of all three sides (in feet) are = 15, 14, and 18 feet

Step-by-step explanation:

Perimeter of Triangle = 47ft

Let the one side be 'x'

<em>Side 1 = x</em>

One side of the triangle is one foot longer than the second side

<em>Side 2 = x - 1</em>

<em>The third side is four feet longer than the second side</em>

<em>Side 3 = (x - 1) + 4</em>

<em />

<em>Perimeter = sum of all sides</em>

<em>47 = x + (x - 1) + (x - 1) + 4</em>

<em>47 = x + x - 1 + x - 1 + 4</em>

<em>47 = 3x + 2</em>

<em>47 - 2 = 3x</em>

45 = 3x

<u>x = 15</u>

substitute for x in each of the sides

<em>Side 1 = x                   => </em><em>15 feet</em>

<em>Side 2 = x - 1              => 15 - 1 = </em><em>14 feet</em>

<em>Side 3 = (x - 1) + 4      => 14 + 4 = </em><em>18 feet</em>

6 0
3 years ago
Read 2 more answers
A circle has an area of 78.5 square inches what is the radius of the circle
Alinara [238K]

Answer:

Step-by-step explanation:

Area of circle = 78.5 in²

πr² = 78.5

3.14*r² = 78.5

r^{2}=\frac{78.5}{3.14}\\\\=\frac{78.5*100}{3.14*100}\\\\=\frac{7850}{314}\\\\r^{2}=25\\r=\sqrt{25}=\sqrt{5*5}\\\\

r =  5 in

3 0
3 years ago
Read 2 more answers
A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and
natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0
3 years ago
– 7 (2W - 5)<br> Simplify by using the distributive property and then combine like terms PLEASE
Artemon [7]
-14W + 35. Can’t simplify any further
6 0
3 years ago
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