All categories

4 years ago

(5m+100) (2m+10) what’s the value of m

Mathematics

1 answer:

Alexeev081 [22]4 years ago

6 0

Answer:

m=-30

Step-by-step explanation:

5m+100=2m+10

We want to get the variable on one side of the equation. First we subtract 100 from both sides.

5m=2m-90

Subtract 2m from both sides.

3m=-90

Divide both sides by 3.

m=-30

You might be interested in

Describe the domain and range of y=2(3)^x-2+5

allochka39001 [22]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

How do u solve <br> 1×-2y=4<br> -1×+10y=8

Molodets [167]

Answer: x = -8 ; y = -6

Step-by-step explanation:

1*x-2*y=4

1*x = 4 + 2*y

x = 4 + 2*y

Now you replace the value of x on the following equation:

-1*x+10*y=8

-1*(4 + 2*y) = 8

-4 - 2*y = 8

-2*y = 8+4

-2*y = 12

y = -12/2

y = -6

You replace the value of y in the previous equation:

x = 4 + 2*y

x = 4 + 2*(-6)

x = 4 - 12

x = -8

6 0

3 years ago

25% of 395? Please show work

velikii [3]

395 *25% could also be interpreted as 395/4
395 = 98.75
4

7 0

3 years ago

Read 2 more answers

Tia performed an experiment where she flipped a coin 200 times. The coin landed heads up 92 times and tails up 108 times. Which

11111nata11111 [884]

only the first statement is true - it is the experimental probability. the rest is incorrect: the ratio is not the number of trials; the theoretical probability should be 0.5 (for unbiased coins); ratio never represents a number of occurences.

4 0

4 years ago

Read 2 more answers

SinA=√1-x÷√1+X<br> Find the value of cosA

Irina-Kira [14]

The value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

<h3>Trigonometric ratios</h3>

It is important to note that

sin A = opposite/ hypotenuse

cos A = adjacent/ hypotenuse

Then,

opposite = $\sqrt{1} - x$

Hypotenuse = $\sqrt{1} + x$

Let's find the adjacent side using the Pythagorean theroem

$(\sqrt{1} + x)^2 = (\sqrt{1 -x } )^2 + x^2$

$1 + x^2 = 1 - x^2 + x^2$

$x = \sqrt{\frac{1 + x^2}{1 -x^2} }$

cos A = x/hypotenuse

$cos A = \frac{\sqrt{\frac{1+x^2}{1 -x^2} } }{\sqrt{1} +x}$

cos A = √(1 + x²)/ (1 - x²) /√1 + x

Thus, the value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

Learn more about trigonometric identities here:

brainly.com/question/7331447

#SPJ1

6 0

2 years ago