In order to solve for a, we must isolate it. To do this, we should add c to both sides, making a the only term on the left.
Final answer: a=c+d-r
Answer:
a) 95% of the widget weights lie between 29 and 57 ounces.
b) What percentage of the widget weights lie between 12 and 57 ounces? about 97.5%
c) What percentage of the widget weights lie above 30? about 97.5%
Step-by-step explanation:
The empirical rule for a mean of 43 and a standard deviation of 7 is shown below.
a) 29 represents two standard deviations below the mean, and 57 represents two standard deviations above the mean, so, 95% of the widget weights lie between 29 and 57 ounces.
b) 22 represents three standard deviations below the mean, and the percentage of the widget weights below 22 is only 0.15%. We can say that the percentage of widget weights below 12 is about 0. Equivalently we can say that the percentage of widget weights between 12 an 43 is about 50% and the percentage of widget weights between 43 and 57 is 47.5%. Therefore, the percentage of the widget weights that lie between 12 and 57 ounces is about 97.5%
c) The percentage of widget weights that lie above 29 is 47.5% + 50% = 97.5%. We can consider that the percentage of the widget weights that lie above 30 is about 97.5%
The is the concept of algebra, the weight of the spring can be modeled by the equation;
w=0.9sqrt E
where;
=energy in joules;
thus the weight of the spring when the energy is 12 j will be:
w=0.9sqrt12
w=3.18 g
Answer:
-2 < AC < 8
Step-by-step explanation:
The last side has to be less than the sum of the other 2 sides, or less than 8. The only answer choice with this is the 3rd one.
Answer:
The point slope form of that graph would be D) y + 7 = 2/5(x + 4)
Step-by-step explanation:
We know this by plugging into the point-slope form of the equation, which is listed below.
y - y1 = m(x - x1)
y - -7 = 2/5(x - -4)
y + 7 = 2/5(x + 4)