Question

Help with this question? I got half of it, but can't seem to get the other half. Please explain how you got your answer. Thanks!

Answer 1

X - Intercept
    x + 3y + 2z = 6
x + 3(0) + 2(0) = 6
        x + 0 + 0 = 6
              x + 0 = 6
                 - 0  - 0
                    x = 6
X - Intercept: (6, 0, 0)

Y - Intercept
  x + 3y + 2z = 6
0 + 3y + 2(0) = 6
    0 + 3y + 0 = 6
    0 + 0 + 3y = 6
          0 + 3y = 6
        - 0         - 0
                3y = 6
                 3     3
                  y = 2
Y - Intercept: (0, 2, 0)

Z - Intercept
x + 3y + 2z = 6
0 + 3(0)  2z = 6
  0 + 0 + 2z = 6
        0 + 2z = 6
      - 0         - 0
              2z = 6
               2     2
                z = 3
Z - Intercept: (0, 0, 3)

Volume of the X - Intercept, Y - Intercept, and Z - Intercept
V = ¹/₃(¹/₂lwh)
V = ¹/₃(¹/₂(6)(2)(3))
V = ¹/₃(¹/₂(12)(3))
V = ¹/₃(¹/₂(36))
V = ¹/₃(18)
V = 6 u³

Answer 2

Answer:

Volume of the pyramid = 6 cubic units

Step-by-step explanation:

The volume of a triangular pyramid is: V = (1/3)*A*H

where A is the area of the triangle base, and H is the height of the pyramid.

Taking the triangle formed in the x-y plane as the base, its area is computed as follows:

A = (1/2)*6*2 = 6 square units

where 6 and 2 are the measure of the two perpendicular sides of the triangle.  This is taken from the x-intercept point  (6, 0, 0) and  y-intercept point  (0, 2, 0).

The height of the pyramid is then the measure of the z-intercept point (0, 0, 3), that is, 3. Replacing in volume formula:

V = (1/3)*A*H

V = (1/3)*6*3

V = 6 cubic units