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suter [353]
3 years ago
15

Translate the following statement into a mathematical equation:

Mathematics
2 answers:
sleet_krkn [62]3 years ago
8 0
(6+4)n =18 is the answer
dem82 [27]3 years ago
3 0

Answer: (6 + 4)n = 18

(6 + 4)n = 18= a

a=(6 + 4)n = 18

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7. A city lot is twice as long as it is wide, If its perimeter is 480 units, what are the dimensions of the lot?
g100num [7]

Answer:

Step-by-step explanation:

P = 480

P = 2 length + 2 width

but we also know that

2width = length

so plug that into the length

P = 2(2width) + 2 width

480 = 4 width + 2 width

480 = 6 width

80 = width

160= length

see?

3 0
3 years ago
Tina is finding the quotient of. Is she correct? If not, what changes should be made?
Mice21 [21]

For this case, we must find the quotient of

(15x ^ 3 + 12x ^ 2-9x) divided by3x, to verify if Tina was correct.

So:

\frac {15x ^ 3 + 12x ^ 2-9x} {3x} =\\\frac {15x ^ 3} {3x} + \frac {12x ^ 2} {3x} - \frac {9x} {3x} =\\5x ^ 2 + 4x-3

So, Tina was wrong, she had to divide by 3x.

Answer:

Option B


5 0
3 years ago
BRAINLIEST + 10 POINTS
VARVARA [1.3K]

Answer:

what am I supposed to anwser

7 0
3 years ago
Read 2 more answers
Francisco is making an effort to drink more water, and has set a goal of 2 liters per day. He wants to know the volume of the wa
GarryVolchara [31]

Answer:

The volume of water bottle Francisco takes to school = 1.0048 liters

Step-by-step explanation:

The dimensions of the water bottle are given :

The Height of the water bottle is 20 cm  

⇒ h = 20 cm

The Radius of the water bottle is 4 cm

⇒ r = 4 cm

⇒ Volume of the water bottle = π·r²·h

⇒ Volume = 3.14 × 4² × 20

⇒ Volume = 1004.8 cm³

Now, 1000 cm³ = 1 liter

⇒ 1004.8 cm³ = 1.0048 liter

Hence, The volume of water bottle Francisco takes to school = 1.0048 liters

3 0
3 years ago
Read 2 more answers
[Geometry Basics] I'm just checking if this is correct:
Leno4ka [110]
\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ x &,& y~) 
%  (c,d)
&&(~ -9 &,& -1~)
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)
\\\\\\
\left( \cfrac{-9+x}{2}~~,~~\cfrac{-1+y}{2} \right)=\stackrel{midpoint}{(8,14)}\implies 
\begin{cases}
\cfrac{-9+x}{2}=8\\\\
-9+x=16\\
\boxed{x=25}\\
-------\\
\cfrac{-1+y}{2} =14\\\\
-1+y=28\\
\boxed{y=29}
\end{cases}

\bf -------------------------------\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ x &,& y~) 
%  (c,d)
&&(~10 &,& 12~)
\end{array}\qquad
\\\\\\
\left( \cfrac{10+x}{2}~~,~~\cfrac{12+y}{2} \right)=\stackrel{midpoint}{(6,9)}\implies 
\begin{cases}
\cfrac{10+x}{2}=6\\\\
10+x=12\\
\boxed{x=2}\\
-------\\
\cfrac{12+y}{2} =9\\\\
12+y=18\\
\boxed{y=6}
\end{cases}
3 0
3 years ago
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