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Ganezh [65]
3 years ago
7

A box of muffin mix has dimensions of 5 3/8 inches by 3 inches by 1 5/8 inches. What is the volume of the box? 15 15/64 cubic in

ches, 26 13/64 cubic inches, 21 cubic inches, 30 cubic inches
Mathematics
2 answers:
anyanavicka [17]3 years ago
7 0
Answer is 26 13/64

first u need to simplify mixed number then multiply them all

43/8*3*13/8=1677/64
DedPeter [7]3 years ago
7 0

Answer:

Step-by-step explanation:

answer is 26 13/64

first u need to simplify mixed number then multiply them all

43/8*3*13/8=1677/64

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If I charged 30$ a hair cut the whole year how many times would each customer have to come in to get 17,510$
V125BC [204]
You would need to come in 583.6 or 584 times
5 0
3 years ago
Find all the solutions for the equation:
Contact [7]

2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0

Divide both sides by x^2\,\mathrm dx to get

2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}

Substitute v(x)=\dfrac{y(x)}x, so that \dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}. Then

x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}

x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}

x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}

The remaining ODE is separable. Separating the variables gives

\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x

Integrate both sides. On the left, split up the integrand into partial fractions.

\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}

\implies v^2+2v+1=a(v^2+1)+(bv+c)v

\implies v^2+2v+1=(a+b)v^2+cv+a

\implies a=1,b=0,c=2

Then

\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v

On the right, we have

\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C

Solving for v(x) explicitly is unlikely to succeed, so we leave the solution in implicit form,

\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C

and finally solve in terms of y(x) by replacing v(x)=\dfrac{y(x)}x:

\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C

\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C

\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}

7 0
3 years ago
How to simply 7a+3(9+5a)?
makvit [3.9K]
To solve for this, we need to use the Distributive Property, which allows us to multiply the number/variable outside of the parenthesis by all numbers/variables inside of the parenthesis. Once we've done that, we can attempt to simplify the equation.
Our current equation is:
7a + 3(9+5a) = 0
Let's use the Distributive Property.
3(9 + 5a)
3(9) + 3(5a)
27 + 15a
Our current equation now is:
7a + 27 + 15a = 0
Combine like-terms.
15a + 7a = 22a
22a + 27 (If this is not being solved, THIS is your answer as an expression)
Subtract 27 from both sides
22a = -27
Divide both sides by 22 to get a.
a = -27/22.
If we are not solving for a, but getting an expression, your answer is:
22a + 27.
If we are solving for a, our answer is:
a = -27/22.
I hope this helps!
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pi*36
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157.70 for 19 shirts
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Answer:

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Step-by-step explanation:

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