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Ganezh [65]
3 years ago
7

A box of muffin mix has dimensions of 5 3/8 inches by 3 inches by 1 5/8 inches. What is the volume of the box? 15 15/64 cubic in

ches, 26 13/64 cubic inches, 21 cubic inches, 30 cubic inches
Mathematics
2 answers:
anyanavicka [17]3 years ago
7 0
Answer is 26 13/64

first u need to simplify mixed number then multiply them all

43/8*3*13/8=1677/64
DedPeter [7]3 years ago
7 0

Answer:

Step-by-step explanation:

answer is 26 13/64

first u need to simplify mixed number then multiply them all

43/8*3*13/8=1677/64

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Find the slope and reduce P=(-2,3) Q=(8,3)
Tanya [424]

Answer:

∆y/∆x=y2-y1/x2-x1

=3-3/(-2+3)

=0/1

=o I.e it is undefine

7 0
4 years ago
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Laura takes very good care of her vehicles. She owns a blue van and a red truck. Although she bought them both new, she has owne
MrRissso [65]

The age of the van owned = 12 years

The age of the truck owned  = 29 years

Step-by-step explanation:

Here, the given question is INCOMPLETE.

Laura takes very good care of her vehicles. She owns a blue van and a red truck. Although she bought them both new, she has owned the truck for 17 years longer than she has owned the van. If the sum of the ages of the vehicles is 41 years, how old is the van and how old is the truck?

Let us assume the number of years Laura has owned the van = S years

So, according to the question:

The number of years she has owned truck = S + 17 years

Now, Sum of the age of ( Truck + Van)  = 41 years

⇒ (S + 17 years) + (S years)  = 41 years

or, 2 S +  17 = 41

or, 2 S  = 4 1 -1 7 = 24

or, S  = 24/2 = 12 years

or, S  = 12 years

Hence the age of the van owned = 12 years

The age of the truck owned  = S  + 17  = 12 + 17 = 29 years

6 0
3 years ago
Gina has 20 groups of 10 pencils. 137 are sharpened. How many dull pencils does Gina have?
yarga [219]
If there are 20 groups of 10, then there are 200 pencils. Subtract 200 and 137 to get the number of dull pencils.
5 0
3 years ago
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What is 30% of 20??Help me please
Nuetrik [128]
Taking 30% percent of something is the same as multiplying by .3

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7 0
3 years ago
Write a system of linear inequalities so the points (1, 2) and (4, -3) are solutions of the system, but the point (-2, 8) is not
Verizon [17]

Answer: \left \{ {{y\leq -\frac{5}{3}x + \frac{11}{3}} \atop {y < 8}} \right

<u>Step-by-step explanation:</u>

(1, 2) and (4, -3)

First, find the slope (m): \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m = \frac{-3-2}{4-1}

   = -\frac{5}{3}

Next, choose ONE of the points and input the point and slope into the Point-Slope formula: y - y₁ = m(x - x₁)

y - 2 = -\frac{5}{3}(x - 1)

y - 2 = -\frac{5}{3}x + \frac{5}{3}

y      = -\frac{5}{3}x + \frac{11}{3}

Then, determine which inequality symbol will result in (-2, 8) being False (since it is not a solution):

y ___ -\frac{5}{3}x + \frac{11}{3}

8 ___ -\frac{5}{3}(-2) + \frac{11}{3}

8 ___ \frac{1}{3}

8 > \frac{1}{3}

so ≤ makes the statement False

⇒ y ≤ -\frac{5}{3}x + \frac{11}{3}

****************************************************************

If you need a "system" of inequalities, then you need another equation.

There are infinite possibilities. Graph the points to see what works.  

y < 8   or  x > -2 are two examples.


---> I just realized that the system can be simpler than what I did above:

\left \{ {{x>-2} \atop {y < 8}} \right



4 0
3 years ago
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