Type into your calculator (if you haven't already): log 54.
My result: was similar to yours.
Note, however, that we're supposed to round off these results to the nearest thousandths (not thousand).
Your 1.73239 would need to be rounded off to 1.732, with 2 being the nearest thousandths.
Answer:
C
Step-by-step explanation:
move the x over
-x+y=6
move the y over
-x = -y+6
times each number by a -
x=y-6
PEMDAS is
Parenthesis
Exponets
Multiply
Divide
Add
Subtract
therefore, you would do 40*0=0+40+1=41
Step-by-step explanation:
the max. value is when the smaller set (A) is completely contained in the larger set (B).
then n(A n B) is n(A) = 50.
the set intersection between A and B cannot get bigger than that. or A gets bigger ...
after all, the intersection means it is a set of all elements that exist in BOTH sets.
but then there must be other elements besides A and B in the universal set too, because n(universal set) = 96, and n(A u B) would be only 60.
the min. value could be the empty set or 0. but because n(universal set) = 96, and n(A) + n(B) = 110 and larger than 96, it means that there have to be some shared elements. at least 110 - 96 = 14 elements.
in this case there cannot be other elements in the universal set than A and B. and n(universal set) = n(AuB) = 96.
Sorry I don’t know how to type it