Answer:
d. 944 mm^3
Step-by-step explanation:
The area of a circle is given by ...
A = πr² . . . . . where r is the radius, half the diameter
The area of a circle with diameter 9 mm is ...
A = π(4.5 mm)² = 20.25π mm²
The area of the semi-circular end of the prism is half this value, or ...
semicircle area = (1/2)(20.25π mm²) = 10.125π mm² ≈ 31.809 mm²
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The area of the rectangular portion of the end of the prism is the product of its width and height:
A = wh = (9 mm)(6 mm) = 54 mm²
Then the base area of the prism is ...
base area = rectangle area + semicircle area
= (54 mm²) +(31.809 mm²) = 85.809 mm²
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This base area multiplied by the 11 mm length of the prism gives its volume:
V = Bh = (85.809 mm²)(11 mm) ≈ 944 mm³
The volume of the composite figure is about 944 mm³.
Answer:
137.5 Miles
Step-by-step explanation:
2 = 50 Right? So if you were to divide 50 by 2, you would get 1 = 25. All you would have to do from there would be to multiply 25 times 5.5 to get 137.5.
Answer:
Rolling case achieves greater height than sliding case
Step-by-step explanation:
For sliding ball:
- When balls slides up the ramp the kinetic energy is converted to gravitational potential energy.
- We have frictionless ramp, hence no loss due to friction.So the entire kinetic energy is converted into potential energy.
- The ball slides it only has translational kinetic energy as follows:
ΔK.E = ΔP.E
0.5*m*v^2 = m*g*h
h = 0.5v^2 / g
For rolling ball:
- Its the same as the previous case but only difference is that there are two forms of kinetic energy translational and rotational. Thus the energy balance is:
ΔK.E = ΔP.E
0.5*m*v^2 + 0.5*I*w^2 = m*g*h
- Where I: moment of inertia of spherical ball = 2/5 *m*r^2
w: Angular speed = v / r
0.5*m*v^2 + 0.2*m*v^2 = m*g*h
0.7v^2 = g*h
h = 0.7v^2 / g
- From both results we see that 0.7v^2/g for rolling case is greater than 0.5v^2/g sliding case.
Answer:3003
Step-by-step explanation:
14 choose 6 is 3003 because 14!/6!(14-6)!=9*10*11*12*13*14/6!=3003
Answer:
To live your life your own way?
Step-by-step explanation: