Answer:
C
Step-by-step explanation:
We have: (I rewrote the function)

Given that:

The first iterate will be:

The second iterate will be:

And the third iterate will be:

Hence, our answer is C.
ANSWER
No real roots.
The roots are complex or imaginary.
EXPLANATION
The quadratic equation

has discriminant,

If the discriminant is less than zero , then the quadratic equation has no real roots.
The given discriminant is -9.
Since -9 is less than zero, it means the quadratic equation has complex or imaginary roots.
Answer:
2097150
Step-by-step explanation:
<u>GIVEN :-</u>
- First term of G.P. = 6
- Forth term of G.P. = 384
<u>TO FIND :-</u>
- Sum of first 10 terms of the G.P.
<u>CONCEPT TO BE USED IN THIS QUESTION :-</u>
<em>Geometric Progression :-</em>
- It's a sequence in which the successive terms have same ratio.
- General form of a G.P. ⇒ a , ar , ar² , ar³ , ....... [where a = first term ; r = common ratio between successive terms]
- Sum of 'n' terms of a G.P. ⇒
.
<em>[NOTE :- </em>
can also be the<em> formula for "Sum of n terms of G.P." because if you put 'r' there (assuming r > 0) you'll get negative value in both the numerator & denominator from which the negative sign will get cancelled from the numerator & denominator. </em><em>YOU'LL BE GETTING THE SAME VALUE FROM BOTH THE FORMULAES.</em><em>]</em>
<u>SOLUTION :-</u>
Let the first term of the G.P. given in the question be 'a' and the common ratio between successive terms be 'r'.
⇒ a = 6
It's given that <u>forth term</u> is 384. So from "General form of G.P." , it can be stated that :-


Divide both the sides by 6.


![=> r = \sqrt[3]{64} = 4](https://tex.z-dn.net/?f=%3D%3E%20r%20%3D%20%5Csqrt%5B3%5D%7B64%7D%20%3D%204)
Sum of first 10 terms 


