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3 years ago

You use 2 1/3 feet of string to make one bracelet. How many can you make with 10 1/2 feet of string?

Mathematics

2 answers:

matrenka [14]3 years ago

7 0

4 and one half. 10 1/2 divided by 2 1/3 equals 4 1/2

Vesna [10]3 years ago

5 0

Answer:4.5

Step-by-step explanation:

10 1/2÷2 1/3

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What is 19.6 divided by 7

Lemur [1.5K]

19 divided by 7 = 2.8

7 0

3 years ago

Find the first three iterates of the function f(z) = z2 + c with a value of c = 2 - 3i and an initial value of z0 = 1 + 2i.

Artist 52 [7]

Answer:

Step-by-step explanation:

We have: (I rewrote the function)

$f(z_n)={z_{n-1}} ^2+c$

Given that:

$\displaystyle c=2-3i \text{ and } z_0 = 1 + 2 i$

The first iterate will be:

$\displaystyle \begin{aligned} f(z_1)&=(z_0)^2+c \\ &=(1+2i)^2+(2-3i) \\ &= (1+4i+4i^2)+(2-3i) \\ &=1+4i-4+2-3i \\ &=-1+i \end{aligned}$

The second iterate will be:

$\begin{aligned}f(z_2) &=(z_1)^2+c\\ &=(-1+i)^2+(2-3i) \\&= (1-2i+i^2)+(2-3i) \\&=1-2i-1+2-3i \\&=2-5i \end{aligned}$

And the third iterate will be:

$\begin{aligned} f(z_3)&=(z_2)^2+c\\ &=(2-5i)^2+(2-3i) \\ &=(4-20i+25i^2)+(2-3i) \\ &=4-20i-25+2-3i \\ &=-19-23i \end{aligned}$

Hence, our answer is C.

3 0

2 years ago

If the discriminant of a quadratic equation is equal to -9, which statement describes the roots?

Mice21 [21]

ANSWER

No real roots.

The roots are complex or imaginary.

EXPLANATION

The quadratic equation

$a {x}^{2} + bx + c = 0$

has discriminant,

$D = {b}^{2} - 4ac$

If the discriminant is less than zero , then the quadratic equation has no real roots.

The given discriminant is -9.

Since -9 is less than zero, it means the quadratic equation has complex or imaginary roots.

8 0

3 years ago

Solve the quadratic equation with there being two solutions

jeyben [28]

4a^2=9
a^2=9/4
a=3/2
a=-3/2

7 0

2 years ago

The first term of a geometric sequence is 6 and the fourth term is 384. What is the sum of the first 10 terms of the correspondi

aleksandrvk [35]

Answer:

2097150

Step-by-step explanation:

GIVEN :-

First term of G.P. = 6
Forth term of G.P. = 384

TO FIND :-

Sum of first 10 terms of the G.P.

CONCEPT TO BE USED IN THIS QUESTION :-

Geometric Progression :-

It's a sequence in which the successive terms have same ratio.

General form of a G.P. ⇒ a , ar , ar² , ar³ , ....... [where a = first term ; r = common ratio between successive terms]

Sum of 'n' terms of a G.P. ⇒ $\frac{a(r^n - 1)}{r-1}$ .

[NOTE :- $\frac{a(1-r^n)}{1-r}$ can also be the formula for "Sum of n terms of G.P." because if you put 'r' there (assuming r > 0) you'll get negative value in both the numerator & denominator from which the negative sign will get cancelled from the numerator & denominator. YOU'LL BE GETTING THE SAME VALUE FROM BOTH THE FORMULAES.]