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mrs_skeptik [129]
3 years ago
13

The first and second year’s sales for a company were $328,000 and $565,000. The expenses for the first year were $117,000. The c

ompany had a net profit of $113,000 after two years.
What were the company's expenses for the second year?



A.
$230,000


B.
$354,000


C.
$663,000


D.
$776,000
Mathematics
1 answer:
Serhud [2]3 years ago
6 0
As a disclaimer, I can't say I'm completely confident in this answer. Use at own risk.

Formulas:

Year 1: 328,000 (sales) - 117,000 (expense) = 211,000 (profit)

Year 2: 565,000 (sales) - x (expense) = y (profit)

Net Profit: 211,000 + y = 113,000

Math

211,000 (profit y1) + 565,000 (sales y2) = 776,000

776,000 - 113,000 (net profit) = -663,000 (expenses)

Confirm:

Net Profit: 211,000 + y = 113,000 (listed in formulas, just a reminder)

Plug in: 565,000 (y2 sales) - 663,000 (our solution) = -98,000

211,000 (y1 net) + -98,000 (our plug in) = 113,000 (2 year net profit given to us)
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Answer:

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Step-by-step explanation:

We know that a function is a relation where each input or x-value of the X set has a unique y-value or output of the Y set.

In other words, we can not have duplicated inputs as there should be only 1 output for each input.

If we closely observe relation B, and E i.e.

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Relation 'B' IS NOT A FUNCTION

Relation B has duplicated or repeated inputs i.e. x = 3 appears twice times. we can not have duplicated inputs as there should be only 1 output for each input.

Thus, relation B is NOT a function.

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Thus, relation B is NOT a function.

Therefore, relations B and E do not represent the function.

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3 years ago
The sum of Eric’s and Bob’s weights is 9 times the difference of their weights. The positive difference of their weights is also
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Answer:

<u>150</u>

Step-by-step explanation:

So I will shorten Eric, and Bob's names as E, and B.

So the equations are this

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Move the variables and you get

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Just divide them both by -2

and E=120

So when we know the value of E we can just plug it into the 1st question

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8B=1200

1200/8= 150

B=150

There is Bob's weight

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