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BARSIC [14]
3 years ago
6

If the area of a square 1 is 250 units squared and the area of square 3 is 120 units squared, what is the area of square 2 ? HEL

P PLEASE
Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
8 0
180 units squared is the answer
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Pls help and explain it how i do i this <3
jolli1 [7]

Answer:

You input the equation they give you into the table to get an outcome. The Equation they gave you is x=y. simply, what ever X is, thats what y is. x=y. On the table it says that X is 3. If x is 3 then y is three because they are equal. if X is 7 then Y is 7. its the same throughout the whole table. To write it as an ordered pair you write (X,Y) if x is three y is three so the ordered pair would look like (3,3)

4 0
2 years ago
PLEASE ANSWER VERY VERY QUICKLY! GIVING BRAINIEST 3x 3 + 1 over 4 x 4 with the power of 2 how would you solve this?
Orlov [11]

Answer:

FRACTION: 10         (10 OVER 256)

                   __

                  256

Step-by-step explanation:

3 x 3 is 9, plus 1 is 10

4x4 is 16, and 16² is 256

5 0
3 years ago
25 POINTS
Semenov [28]

If the slope of AB = CD and BC = AD it's a parallelogram:

Slope of AB = 6+1 / -9+5 = -7/4

CD = -2-5 / 3+1 = -74

These are equal.

BC = 5-6 / -1 +9 = -1/8

AD = -2 +1 / 3+5 = -1/8

These are also equal so it is a parallelogram.

Now to find if the diagonals are perpendicular find the slope of the perpensicular points:

AC = 5 +1 / -1 +5 = 6/4 = 3/2

BD = 6+2 / -9 -3 = 8/-12 = -2/3

Because BD is the reciprocal of AC, this means they are perpendicular.

And because AB is not perpendicular to AD ( AB and AD are not reciprocals) it is a rhombus.

5 0
3 years ago
Shark Inc. has determined that demand for its newest netbook model is given by lnq−3lnp+0.004p=7ln⁡q−3ln⁡p+0.004p=7, where q is
olga2289 [7]
  <span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q: 

(1/q)(dq/dp) − 3/p + 0.003 = 0 
dq/dp = (3/p − 0.003)q. 

So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p. 

b) The revenue is pq. 
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1: 

3 − 0.003p = −1 
0.003p = 4 
p = 4/0.003 = 4000/3 = 1333.33</span>
8 0
3 years ago
1)
den301095 [7]
B

Subtract 2x from the left side and the right side. Then you get -y = -2x+6. The divide each side by negative 1. Thus getting you to an answer of y = 2x-6
3 0
3 years ago
Read 2 more answers
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