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Nat2105 [25]
3 years ago
8

To compute a student's Grade Point Average (GPA) for a term, the student's grades for each course are weighted by the number of

credits for the course. Suppose a student had these grades: 3.7 in a 5 credit Math course 1.8 in a 3 credit Music course 2.8 in a 5 credit Chemistry course 2.8 in a 4 credit Journalism course What is the student's GPA for that term
Mathematics
1 answer:
tia_tia [17]3 years ago
4 0

Answer:

2.89, rounded to the nearest hundredth

Step-by-step explanation:

Given that GPA is weighted by credits, we must first multiply each grade by its credit amount and sum those up to weigh the credits. Then, we divide by the total amount of credits to get the GPA per credit.

So, we start with math,

3.7 *5 + 1.8 *3 + 2.8 * 5 + 2.8 * 4 = 49.1 as the total GPA weighted per credit.

Then, to find the average per credit, we divide by the total amount of credits, which is 5 + 3 + 5 + 4 = 17.

Our answer is 49.1/17 = 2.89, rounded to the nearest hundredth

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Dan invests £1300 into his bank account.
alexandr402 [8]

Given parameters:

Principal  = £1300

Interest rate  = 5%

Duration  = 2yrs

Unknown:

Total amount of Dan's principal = ?

To solve this problem, we apply the equation below:

  Total investment worth  = Principal + interest

   Interest  = \frac{PRT}{100}

where P is the principal

          R is the rate

          T is the time

Now, input the parameters;

     Total investment worth  = £1300 + £ \frac{1300 x 5 x 2}{100}

                                             = £1300 + £130

                                             = £1430

The amount after two years is £1430

7 0
3 years ago
In a certain community, 36 percent of the families own a dog and 22 percent of the families that own a dog also own a cat. In ad
zysi [14]

Answer:  a) 0.0792   b) 0.264

Step-by-step explanation:

Let Event D = Families own a dog .

Event C = families own a cat .

Given : Probability that families own a dog : P(D)=0.36

Probability that families own a dog also own a cat : P(C|D)=0.22

Probability that families own a cat : P(C)= 0.30

a) Formula to find conditional probability :

P(B|A)=\dfrac{P(A\cap B)}{P(A)}\\\\\Rightarrow P(A\cap B)=P(B|A)\times P(A)   (1)

Similarly ,

P(C\cap D)=P(C|D)\times P(D)\\\\=0.22\times0.36=0.0792

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792

b) Again, using (2)

P(D|C)=\dfrac{P(C\cap D)}{P(C)}\\\\=\dfrac{0.0792}{0.30}=0.264

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264

5 0
3 years ago
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djyliett [7]
Answer:

X= 22

Explanation:

Add 10 to both sides and then x is 22
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fomenos

Answer:

8 inches,

Step-by-step explanation:

2 2/3 = 8/3.

3 * 8/3

= 8 inches,

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