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givi [52]
4 years ago
15

23 POINTS! NINTH GRADE ALGEBRA HOMEWORK PLEASE HELP ASAP!!

Mathematics
1 answer:
DaniilM [7]4 years ago
8 0

\frac{ - b \sqrt{b {}^{2}  - 4 \times a \times b} }{ - 2 \times a}
a =  {x}^{2}  \\ b = x \\ c = 12
\frac{ - ( - 2) \sqrt{ { - 2}^{2}  - 4 \times 2(x)\times  - 12} }{  -  2 \times 2}
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Shawna reduced the size of a rectangle to a height of 2 in. What is the new width if it was originally 24 in wide and 12 in tall
miskamm [114]

Answer:

4 inches.

Step-by-step explanation:

The height of a rectangle is reduced by Shawna to a size of 2 inches.

The original width of the rectangle was 24 inches and the height was 12 inches.

If the ratio of width to height remains the same, then we can find the new width.

If the new width is x inches then, we can write

\frac{x}{2} = \frac{24}{12}

⇒ x = 4 inches. (Answer)

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2 years ago
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Triangle ABC is reflected over the Y axis. what are the coordinates of the reflected triangle
Liula [17]
Original Coordinates: A(1, 3) B(4, 5) C(3, 1)

Now, It is reflected over y-axis, so the sign of their x-coordinate will change.,

It would be: A'(-1, 3) B'(-4, 5) C'(-3, 1)

Hope this helps!
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3 years ago
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Help ASAP!!!<br> Please and thank you
Neporo4naja [7]
‘| |’ means modulus.
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When will the equation p(b)=520(0.88)^b have a value less than 100?
yulyashka [42]

Answer:

The given equation will have value less than 100 whenever the value of b is greater than 12.89

Step-by-step explanation:

For the given equation, p(b) = 520 × 0.88^{b} to have a value less than 100 we can establish inequality as:

                     p(b) < 100

         or,  520 × 0.88^{b} < 100

         or, \frac{520}{520} × 0.88^{b} < \frac{100}{520}

         or, 0.88^{b} < \frac{1}{5.2}

         or, ㏒ ( 0.88^{b} ) < ㏒  (\frac{1}{5.2})

         or, b× ㏒ 0.88 < ㏒  (\frac{1}{5.2})

         or,  \frac{log (\frac{1}{5.2}) }{log (0.88)}   <  b

         or, 12.89 < b

Hence for the equation to have value less than 100, b must be greater than 12.89.

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4 years ago
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