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4 years ago

23 POINTS! NINTH GRADE ALGEBRA HOMEWORK PLEASE HELP ASAP!!

1 answer:

8 0

$\frac{ - b \sqrt{b {}^{2} - 4 \times a \times b} }{ - 2 \times a}$
$a = {x}^{2} \\ b = x \\ c = 12$
$\frac{ - ( - 2) \sqrt{ { - 2}^{2} - 4 \times 2(x)\times - 12} }{ - 2 \times 2}$

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Round your answer to the nearest hundredth.

Natali5045456 [20]

Answer:

uh, I think it's 4.13

Step-by-step explanation:

5*sin(65)=4.13 now this seems a bit off but this was the only one that actually worked

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2 years ago

Plz help me well mark brainliest if you are correct!!.....

emmainna [20.7K]

Step-by-step explanation:

the base is 5unit and the height is 9unit

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3 years ago

Read 2 more answers

Nola Giles down a trail at a steady rate for 10 minutes. Her change in elevation was -200 feet. Then she continued to hike down

lions [1.4K]

Her fastest change in elevation was -200 feet in 10 minutes. She was going at a rate of 20 fpm (feet per minute) compared to 15 fpm.

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3 years ago

Write an equation for the orbit of Saturn in the form x^2/a^2 + y^2/b^2 = 1

frozen [14]

Answer:

x²/2166784 +y²/2159989 = 1

Step-by-step explanation:

The relationship between the semi-axes and the eccentricity of an ellipse is ...

e = √(1 -b²/a²)

In order to write the desired equation we need to find 'b' from 'e' and 'a'.

<h3>semi-minor axis</h3>

Squaring the equation for eccentricity gives ...

e² = 1 -b²/a²

Solving for b², we have ...

b²/a² = 1 -e²

b² = a²(1 -e²)

<h3>ellipse equation</h3>

Using the given values, we find ...

b² = 1472²(1 -0.056²) = 2166784(0.996864) ≈ 2159989

The desired equation is ...

x²/2166784 +y²/2159989 = 1

7 0

2 years ago

The speed of the current in a creek is 5 mph. A person clan kayak 3 mi upstream in the same time that it takes him to kayak 13 m

Brut [27]

Answer:

Step-by-step explanation:

0) the basic formula is: L=v*t, where L - distance, v - speed/velocity; t - time;

1) if the person's speed in still water is 'v' and the speed of water is 5 (according to the condition), then the upstream speed is 'v-5' and the downstream speed is 'v+5';

2) according to the condition the upstream time and the downstream time are the same, it means t₁=t₂=t, where t₁=upstream time and t₂=downstream time;

3) according to the items above it is possible to make up the equation of the upstream travel: t(v-5)=3; ⇒ t=3/(v-5);

4) according to the items above it is possible to make up the equation of the downstream travel: t(v+5)=13; ⇒ t=13/(v+5);

5) if t=3/(v-5) and t=13/(v+5), then

$\frac{3}{v-5} =\frac{13}{v+5}; \ => \ v=8.$

8 0

3 years ago