Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
15x20=300
300 square feet is 33.33333333333333333333333333333333333 square yards (divide by 9)
the answer is 33
Do 2^3 first. It is isolated on one side of a set of the + sign.
{8 + [4*(10 - 6)]} / 3 Next do the innermost
{8 + [4*4]} / 3 Do what's in the square brackets.
{8 + 16} / 3
24/3 Divide by 3
The answer is 8
8 <<<< answer.
9 or -9 ...if I’m wrong sorry
