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qwelly [4]
2 years ago
13

Which is closest to the circumference of the CD?

Mathematics
2 answers:
seropon [69]2 years ago
5 0

Answer:

idk but heres an equation

Step-by-step explanation:

Since  

2

π

r

=

37.68

,

r

=

18.84

π

Area=  

π

⋅

(

18.84

)

2

π

2

=  

354.9456

3.14

= 113.04

Virty [35]2 years ago
5 0

Answer: its eitheir 4 or 3

Step-by-step explanation:

You might be interested in
A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.
irakobra [83]

Answer:

The integral is equal to 5\sec^2(2x)+C for an arbitrary constant C.

Step-by-step explanation:

a) If u=\tan(2x) then du=2\sec^2(2x)dx so the integral becomes \int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C. (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case u=\sec(2x) hence du=2\tan(2x)\sec(2x)dx. We rewrite the integral as \int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C.

c) We use the trigonometric identity \tan(2x)^2+1=\sec(2x)^2 is part b). The value of the integral is 5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C. which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.  

3 0
3 years ago
PLS HELP I WILL GIVE BRAINLY THINGY
VashaNatasha [74]

Answer: The y is going to be 7

Explanation: Because 5y/35 divide 5 both sides cancel the both 5's and y stays by itself and 35/5 equals 7. 7*5= 35

8 0
3 years ago
Factor x^3−5x^2−25x+125
UkoKoshka [18]
(x-5)^2 . ( x+5)
=( x^2 - 10x + 25) . ( x+ 5)
=x^3 + 5x^2 - 10x^2 -50x + 25x + 125
= x^3 - 5x^2 -25x +125
5 0
2 years ago
How do I solve and find x?
Sphinxa [80]

Answer:

x = 76.5

Step-by-step explanation:

\frac{x}{4.5} = 22 - 5

\frac{x}{4.5} = 17

x = 17 x 4.5

x = 76.5

5 0
1 year ago
Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ? f (x) = x3 – 2
Basile [38]

Answer:

A

f(x) = x^3 - 2x^2 -3x + 6

Step-by-step explanation:

According to the Factor Theorem, if (<em>x</em> - <em>k</em>) is a factor of a polynomial P(x), then P(k) must equal zero.

We are given that a polynomial function has the zeros 2, √3, and -√3. So, we can let <em>k</em> = 2, √3, -√3.

So, according to the Factor Theorem, P(2), P(√3) and P(-√3) must equal 0.

Testing each choice, we can see that only A is true:

\displaystyle f(x) = x^3 - 2x^2 - 3x + 6

Testing all three values yields that:

\displaystyle \begin{aligned} f(2) &= (2)^3 - 2(2)^2 -3(2) + 6 \\ &= (8) - (8) -(6) + (6) \\ &= 0\stackrel{\checkmark}{=}0 \\ \displaystyle  f(\sqrt{3}) &= (\sqrt{3})^3 - 2(\sqrt{3})^2 - 3(\sqrt{3}) + 6 \\ &=(3\sqrt{3}) -(6)-(3\sqrt{3}) + 6 \\ &= 0\stackrel{\checkmark}{=}0 \\ f(-\sqrt{3}) &= (-\sqrt{3})^3 - 2(-\sqrt{3})^2 - 3(-\sqrt{3}) + 6 \\ &=(-3\sqrt{3}) -(6)+(3\sqrt{3}) + 6 \\ &= 0\stackrel{\checkmark}{=}0   \end{aligned}

Hence, our answer is A.

3 0
2 years ago
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