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vladimir2022 [97]

3 years ago

8

Oriel has designed a square mural that measures 10feet on each side. Bill has also designed a square mural but his measures y fe

et shorter on each side. Write an expression to represent the area area of bill mural

1 answer:

tatiyna3 years ago

7 0

Area=side^2
10-y is the side
(10-y)^2 is area
aera=100-20y-y²

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Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur

Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

$\sigma$ is parameterized by

$\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle$

for $0\le u\le7$ and $0\le v\le\frac{2\pi}3$ , and a normal vector to this surface is

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle$

with norm

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}$

So the integral of $f(x,y,z)=x^2+y^2+z^2$ is

$\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}$

6 0

3 years ago

A sprinkler sprays water in a circle. the distance from the sprinkler to the outer edge of the circle is 2.5 m

Angelina_Jolie [31]

C) 19.6 m2

Use the formula A=(pi)r2

7 0

2 years ago

I don’t understand stand this question someone please help me with work shown

djyliett [7]

Answer:

60°

please look into the solution down here.

Step-by-step explanation:

since BD bisects it, then the angles should be bisected symmetrically, or in other words, ANGLE ABD = angle DBC,

hence,

4x = 2x +30

2x = 30

x = 15

therefore, angle DBC = 2x + 30 = 2(15) + 30 = 60°.

4 0

3 years ago

If M9=119,what is the sum of the measures 0f 11 and 16?

mote1985 [20]

The answer is: " 132° " .
____________________________________
Note: m∠9 = m∠11 = m ∠16 ;

So; m∠11 + m∠16 = 132 .
____________________________________

7 0

3 years ago

Find the sum of the measures of the interior angles of the figure.

Ivahew [28]

Step-by-step explanation:

Given figure is of HEXAGON.

the sum of the measures of the interior angles of a hexagon

$= \frac{(6 - 2) \times 180 \degree}{6} \times 6 \\ \\ = {4 \times 30 \degree} \times 6 \\ \\ = 720 \degree$

4 0

4 years ago