Where a= next number in the sequence:
a=n(-3) + 6
Answer:
168 meters squared
Step-by-step explanation:
So we know that Jake walked from b to c and d meaning he didn't go from a to b, but we also know that scarlet walked a to b so to find the length we can subtract scarlet's walk by jake's walk or 38-31 which is 7.
So we know the length of one side is 7 so this means we have side a to b and c to d, but we still need to know b to c. So what we can do is get the length of a b c and d and isolate it so that we only have b to c. To do this we get the length of 7 and double it which is 14 and take it away from the 38m
38-14=24
so now we know that the side is 24 and we can solve for the area
24*7=168
so the answer is 168 meters squared
Chapter : Algebra
Study : Math in Junior high school
x = 7 + √40
find √x of √x + 1
= √x + 1
= √(7+√40) + 1
in Formula is :
= √7+√40 = √x + √y
= (√7+√40)² = (√x + √y)²
= 7+√40 = x + 2√xy + y
= 7 + √40 = x + y + 2√xy
→ 7 = x + y → y = 7 - x ... Equation 1
→ √40 = 2√xy → √40 = 2.2√10 = 4√10
= xy = 10 ... Equation 2
substitution Equation 1 to 2 :
= xy = 10
= x(7-x) = 10
= 7x - x² = 10
= x² - 7x + 10 = 0
= (x - 5)(x - 2) = 0
= x = 5 or x = 2
Subsitution x = 5 and x = 2, to equation 1
#For x = 5
= y = 7 - x
= y = 7 - (5)
= y = 2
#For x = 2
= y = 7 - x
= y = 7 - (2)
= y = 5
and his x and y was find :
#Equation 1 :
= x = 5 and y = 2
#Equation 2 :
= x = 2 and y = 5
So that :
√7+√40 = √x + √y
= √7+√40 = √2 + √5
And that is answer of question :
= √2 + √5 + 1
Given:
ft and
ft.

To find:
The value of P.
Solution:
We have,

Substituting
and
, we get




Taking LCM, we get




Therefore, the value of P is
ft.
The radii of the frustrum bases is 12
Step-by-step explanation:
In the figure attached below, ABC represents the cone cross-section while the BCDE represents frustum cross-section
As given in the figure radius and height of the cone are 9 and 12 respectively
Similarly, the height of the frustum is 4
Hence the height of the complete cone= 4+12= 16 (height of frustum+ height of cone)
We can see that ΔABC is similar to ΔADE
Using the similarity theorem
AC/AE=BC/DE
Substituting the values
12/16=9/DE
∴ DE= 16*9/12= 12
Hence the radii of the frustum is 12