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3 years ago

I need help On the question

Mathematics

1 answer:

CaHeK987 [17]3 years ago

5 0

Multiply 5 for both the numbers in the ratio.

you will get 10 boys and 15 girls which sum to 25 players.

Hope this helps :)

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Enrico install the drain pipe that runs a horizontal distance of 172 inches and drops 6 inches from the horizontal is the slope

KiRa [710]

Water will run down the drain at even the slightest slope.

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3 years ago

Which of the following lines is perpendicular to the line Y equals 3X -4?

gizmo_the_mogwai [7]

Answer:

y = -1/3x + 4

Step-by-step explanation:

Perpendicular line are opposite and reciprocal.

So I flip 3x to 1/3 and change both signs. negative to positive and positive to negative.

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3 years ago

Find the indicated side of the triangle

Ksenya-84 [330]

The measurement of the given angle is 30 degree.

Here we use trigonometric ratio rule which is sin theta= opposite/hypotenuse

Here theta = 30 degree, opposite =7 and hypotenuse =a

So we get

sin 30 = 7/a

a= 7/sin 30

And value of sin 30 = 0.5

So we get , a = 7/0.5 = 14

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7 0

4 years ago

Read 2 more answers

Estimate the part of the garden that is planted with tomatoes. Explain how you decided.

strojnjashka [21]

Answer:

Therefore $tomatoes\hspace{0.1cm} patch = \frac{3}{8}\hspace{0.1cm}of\hspace{0.1cm} garden$

Step-by-step explanation:

i) from the figure shown pumpkins and lettuce seem to make up half of the of the garden

ii) the other half of the garden seems to be tomatoes and cucumber.

iii) tomatoes seems to be 3 times that of cucumber.

iv) therefore we can say that tomatoes would make up three fourths of half of the garden which would equal to three eights of the garden.

$tomatoes\hspace{0.1cm} patch = \frac{3}{8}\hspace{0.1cm}of\hspace{0.1cm} garden$

3 0

3 years ago

Two gears are adjusted so that the smaller gear drives the larger one. if the smaller gear of 3.7cm rotates through an angle of

zepelin [54]

Answer:

<em>The larger gear will rotate through 156°</em>

Step-by-step explanation:

<u>Arc Length</u>

The arc length S of an angle θ on a circle of radius r is:

$S = \theta r$

Where θ is expressed in radians.

The smaller gear of r1=3.7 cm drives a larger gear of r2=7.1 cm. The smaller gear rotates through an angle of θ1=300°.

Convert the angle to radians:

$\displaystyle \theta_1=300*\frac{\pi}{180}=\frac{5\pi}{3}$

The arc length of the smaller gear is:

$\displaystyle S_1=\frac{5\pi}{3}\cdot 3.7$

$\displaystyle S_1=\frac{18.5\pi}{3}$

The larger gear rotates the same arc length, so:

$\displaystyle S_2=\frac{18.5\pi}{3}$

$\displaystyle \theta_2\cdot r_2=\frac{18.5\pi}{3}$

Solving for θ2:

$\displaystyle \theta_2=\frac{18.5\pi}{3r_2}$

$\displaystyle \theta_2=\frac{18.5\pi}{3*7.1}$

$\theta_2=2.73\ radians$

$\displaystyle \theta_2=2.73*\frac{180}{\pi}=156$

The larger gear will rotate through 156°

7 0

3 years ago