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Neporo4naja [7]
3 years ago
10

Explain how these two problems are different: 35-15=20 and 43-26=17

Mathematics
2 answers:
professor190 [17]3 years ago
8 0
They do not have the same answer hoped I helped
Hoochie [10]3 years ago
6 0
Because they don't have the same answer
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Sedaia [141]

Answer:

your answer is A. 92.4

Step-by-step explanation:

Diagonal Length = v(92.4² + 50²)

V(8537.76 + 2500)

V(1037:76)

Diagonal Length 105

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Choose choice 3. It will pass through (-2,2) and will be parallel to the equation in the question.
ANSWER CHOICE 3 IS THE ANSWER
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solve the following system of equations. Enter the y-coordinate of the solution. Round your answerto the nearest tenth 5x+2y=7 -
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(12/17, 59/34) is the answer
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The function f(x) changes value when x changes from x0 to x0 + dx. Find the approximation error . Round your answer, if appropri
allochka39001 [22]
The answer to this question is a simple one.
First, you need this formula :
 <span>(<span>x0 </span>+ dx<span>)^2
You need to substitute the values of the formula
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So the answer to this question is .0036

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3 0
3 years ago
Intellectual development (Perry) scores were determined for 21 students in a first-year, project-based design course. (Recall th
Anit [1.1K]

Answer:

The 99% confidence interval is (3.0493, 3.4907).

We are 99% sure that the true mean of the students Perry score is in the above interval.

Step-by-step explanation:

Our sample size is 21.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 21-1 = 20.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 20 and 0.005 in the two-sided t-distribution table, we have T = 2.528

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{0.40}{\sqrt{21}} = 0.0873

Now, we multiply T and s

M = 2.528*0.0873 = 0.2207

Then

The lower end of the interval is the mean subtracted by M. So:

L = 3.27 - 0.2207 = 3.0493

The upper end of the interval is the mean added to M. So:

LCL = 3.27 + 0.2207 = 3.4907

The 99% confidence interval is (3.0493, 3.4907).

Interpretation:

We are 99% sure that the true mean of the students Perry score is in the above interval.

7 0
3 years ago
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