Answer:
Heyy
Step-by-step explanation:
△ABC is a right angled triangle and right angle at B
sinA=
AC
BC
, cosA=
AC
AB
⟹sinA+cosA=
AC
BC
+
AC
AB
=
AC
BC+AB
[We know that sum of two sides of a triangle is greater than the third side]
⟹sinA+cosA>
AC
AC
=1
Hence, sinA+cosA>1
Answer:
Step-by-step explanation:
2x^2-6x+10=0
2(x^2-3x)+10=0
2(x-(3/2))^2-9/4)+10=0
2(x-(3/2))^2+10-9/2=0
2(x-(3/2))^2+(20-9)/2=0
2(x-(3/2))^2+11/2=0
2(x-(3/2))^2=-11/2
square is always positive so there is no solution
Answer:
a. 0
Step-by-step explanation:
1. To find the slope given two points, use the following formula:

2.
would be the second y-value (in the second ordered pair), 2, and
would be the first y-value (in the first ordered pair), also 2.
3. Same for the x-values.
is -2 and
is 4
4. Now plug in the values.

5. This equals
which simplifies to 0
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Sum of the interior angles of any triangle is 180° .
Thus ;


Subtract sides 138°


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Answer:
1. -10
2. -11
Step-by-step explanation: