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d1i1m1o1n [39]
3 years ago
6

What's the answer to my answer answer right ok thanks

Mathematics
1 answer:
Anika [276]3 years ago
6 0
Feel free to ask any questions as to what I did

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The cube of twice a number
raketka [301]

Answer:

The cube of twice a number.

Twice a quantity usually indicates to take two of the things in question; usually this indicates to multiply by 2. Thus "twice a number x" can be written symbolically as 2x. If this is part of a problem, say twice a number x is 6, then we can rewrite algebraically as 2x=6; dividing both sides by 2 yields x=3.

Step-by-step explanation:

have a nice day, please give me brainliest

3 0
3 years ago
A crew must repave a road that is 3/8 miles long. They can repave 1/48 miles per hour. How long will it take the crew to repave
Anika [276]

Answer:

Step-by-step explanation:

3/8 miles long, 1/48 miles per hour

3/8 and 1/48 can have a common denominator, so you make 3/8 into 18/48 by multiplying both the numerator and denmoinator by 6.

18/48 miles long

1/48 per hour

divide: 18/48 divided by 1/48, which turns into 18/48 x 48/1 which equals 18

18 hours

4 0
3 years ago
Evaluate each expression please help(the crossed out ones are irrelevant)
olga nikolaevna [1]
9. 31 + 5 = 36
10. 16 - 4 = 12
12. 9
13. 44 + 34 = 78
14. 101 - 1 = 100

15. -539 ??? 
16. 15 ??
17. |-435| = 435
7 0
2 years ago
Find the volume of the triangular prism.<br> 2.5 m<br> 6 m<br> 3.1 m
ahrayia [7]

Answer:

46.5

Step-by-step explanation:

5 0
2 years ago
A circular swimming pool has a radius of 28ft. There is a path all the way around the pool that's 4ft wide. A fence is going to
Natalka [10]

Answer:

Therefore 200.96 ft.of fencing are needed to go around the pool path.

Step-by-step explanation:

Given, a circular swimming pool has a radius of 28ft. There is a path all the way around the pool. The width of the path 4 ft.

The radius of the outside edge the pool path is

= Radius of the pool + The width of the path

= (28+4) ft

= 32 ft.

To find the length of fencing, we need to find the circumference of outside the pool path.

Here r= 32 ft

The circumference of outside edge of the pool path

=2\pi r

=(2\times 3.14 \times 32) ft

=200.96 ft.

Therefore 200.96 ft.of fencing are needed to go around the pool path.

3 0
3 years ago
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