For this problem, the most accurate is to use combinations
Because the order in which it was selected in the components does not matter to us, we use combinations
Then the combinations are 
n represents the amount of things you can choose and choose r from them
You need the probability that the 3 selected components at least one are defective.
That is the same as:
(1 - probability that no component of the selection is defective).
The probability that none of the 3 selected components are defective is:
Where 
is the number of ways to select 3 non-defective components from 117 non-defective components and 
is the number of ways to select 3 components from 120.
So:
Finally, the probability that at least one of the selected components is defective is:
P = 7.4%
2 y = - x - 12 y = x + 5
- x - 1 = x + 5- 2 x = 5 + 1- 2 x = 6x = - 6 : 2x = - 32 y = - 3 + 52 y = 2y = 1The solution is ( - 3 , 1 ).Answer: x = - 3.
Answer: 9 a^8 b^12 c^16
Step-by-step explanation:
4√81/16a^8b^12c^16
= 4 x 9/4a^8b^12c^16
= 9a^8b^12c^16
Answer:
I think it's the last to they sound way more independent!!!
Mean: Add up the numbers and divide the sum by the number of values in the set.
6 + 9 + 2 + 4 + 3 + 6 + 5 = 35
35 / 7 = 5
Median: Sort the set from the smallest value to the largest value and select the number in the middle. If the count of the set if even, then select the two middle values and take their mean average.
2, 3, 4, 5, 6, 6, 9
^
So, the median average is 5.
Mode: What number appears the most frequently?
The mode of the set is 6 because it appears twice.
Range: Sort the set by ascending order and take the smallest value and subtract that from the largest value in the set.
9 - 2 = 7
The range is 7.
