Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
The answer is a because when u divide that number by 6 u get a whole number
Answer:
- 150π ft²
- 10π ft.
Step-by-step explanation:
Area of the sector :
Finding the area given r = 30 ft. and θ = 60° :
⇒ Area = π × (30)² × 60/360
⇒ Area = π × 900/6
⇒ Area = 150π ft²
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Length of the arc :
Finding the arc length given r = 30 ft. and θ = 60° :
⇒ Arc Length = 2 × π × 30 × 60/360
⇒ Arc Length = 60/6 × π
⇒ Arc Length = 10π ft.
Answer:
x=1
Step-by-step explanation:
-5 - (15x-1) = 2(7x-16) -x
Distribute the negative sign
-5-15x+1 = 2(7x-16)-x
Distribute the 2
-5-15x+1 = 14x -32-x
Combine like terms
-4-15x = 13x-32
Add 15x to each side
-4-15x+15x = 13x+15x-32
-4 = 28x-32
Add 32 to each side
-4+32 = 28x-32+32
28 = 28x
Divide each side by 28
28/28 = 28x/28
1 =x
