For this question the answer would be x=-3 and x=-2
Answer:
The x-coordinate of the point changing at ¼cm/s
Step-by-step explanation:
Given
y = √(3 + x³)
Point (1,2)
Increment Rate = dy/dt = 3cm/s
To calculate how fast is the x-coordinate of the point changing at that instant?
First, we calculate dy/dx
if y = √(3 + x³)
dy/dx = 3x²/(2√(3 + x³))
At (x,y) = (1,2)
dy/dx = 3(1)²/(2√(3 + 1³))
dy/dx = 3/2√4
dy/dx = 3/(2*2)
dy/dx = ¾
Then we calculate dx/dt
dx/dt = dy/dt ÷ dy/dx
Where dy/dx = ¾ and dy/dt = 3
dx/dt = ¾ ÷ 3
dx/dt = ¾ * ⅓
dx/dt = ¼cm/s
The x-coordinate of the point changing at ¼cm/s
Answer: y =21; x = 7√3
have: cos 60° = x/(14√3) = 1/2 => x = 1/2. (14√3) = 7√3
sin 60° = y/(14√3) = (√3)/2 => y = (√3)/2 . 14√3 = 21
Step-by-step explanation:
Answer:
x=2
SK=21
KY=13
SY=34
Step-by-step explanation:
finding x:
SK+KY=SY
13x-5+2x+9=36-x
get x by itself
13x+2x+1x=36+5-9
simplify
16x=32
divide by 16 on both sides
x=2
Now plug in x (2) into the separate formulas
SK:
13(2)-5
26-5
21
KY:
2(2)+9
4+9
13
SY:
36-(2)
34
To double check your answer plug in what you got
SK+KY=SY
21+13=SY
34
and we got 34 above so this is correct.
Steps:
1. Multiply what is in the parentheses
5x + 5 = 5x + 2
2. Subtract 5x on each side
3. 5=2
4. 5 doesn't equal 2 so the equation doesn't have a solution or it is not true.
