Answer:
def average_strings(lst):
total_length = 0
avg = 0
for s in lst:
total_length += len(s)
avg = total_length/len(lst)
return avg
Explanation:
Create a function called average_strings that takes one parameter, lst
Initialize the total length and avg variables
Create a for loop that iterates through the lst. Get each string's length and put it to the total length
When the loop is done, calculate the average, divide total length by length of the lst
Return the average
Answer:
ANSI/TIA/EIA-570-B - Residential telecommunications
ANSI/TIA/EIA-606-A - Administration
ANSI/TIA/EIA-607 - Grounding and Bonding
Explanation:
The first standard is generally used for residential telecommunication. This is mainly for the form of telecommunications used in residential areas. The second standard is mainly used for administrative purposes such as those in offices. Furthermore, the third standard is applicable to grounding and bonding purposes.
Answer:
I think servers and networks.
The OSI model layer that provides a user interface in the form of an entry point for software programs to access the network infrastructure is: application layer.
<h3>What is the
OSI model?</h3>
OSI model is an acronym for open systems interconnection and it comprises seven (7) main layers, which typically starts from the hardware layers (layers in hardware systems) to the software layers (layers in software systems)
<h3>The layers of the
OSI model</h3>
In Computer networking, the seven (7) layers of the OSI model include the following in sequential order;
The uppermost layer of the OSI model which is the "application layer" gives software programs an access to the services that allow internet connection or network infrastructure.
Read more on OSI model here: brainly.com/question/14446612
Answer:
He can define pas follows: Let P be defined on the set of languages accepted by some Turing machine M. Let it be True if 10 ] is 5 and False otherwise.
Explanation:
The domain of P is the SD languages since it is those languages that are accepted by some Turing machine H. P is nontrivial since P({ a, aa, aaa, aaaa, aaaaa, aaaaaa, b, bb, bbb, bbbb, bbbbb, bbbbbb } ) is True and P ( 5 ) is False.
Thus {< M> is a Turing machine and I L I - 5 and I L I - 16 }
