Answer:
years 1–4: 62.4 bass per year
years 5–8: 67.6 bass per year
Step-by-step explanation:
If the population in year n is ...
p(n) = 3000·1.02^n
then the average rate of change from year 1 to year 4 is ...
(p(4) -p(1))/(4 -1) = 3000(1.02^4 -1.02^1)/3 = 1020·(1.02^3 -1) ≈ 62.4
The average rate of change for years 1–4 is 62.4 bass per year.
For years 5–8, the rate of change is similarly computed:
(p(8) -p(5))/(8 -5) = 3000(1.02^8 -1.02^5)/3 = 1000·1.02^5·(1.02^3 -1) ≈ 67.6
The average rate of change for years 5–8 is 67.6 bass per year.
9514 1404 393
Answer:
p = 0
Step-by-step explanation:
The graph is of an exponential function. An exponential function always has a horizontal asymptote of 0.
p(t) = 5×2^t
p(t) → 0 as x → -∞
The horizontal asymptote is p = 0.
B because anything multiplied by 0 is equal to 0.
Answer:
deeznutshehehehehe
Step-by-step explanation:
lolol gegegeheheh
